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Ronch [10]
3 years ago
12

Some help with these would be much appreciated

Chemistry
1 answer:
alexira [117]3 years ago
7 0

Answer:

4. p

5.p

Explanation:

i just took the quiz and got a 100

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2. Use the Henderson-Hasselbalch equation to estimate the pH of a buffer solution that is composed of 20 mL of 10 M sodium forma
Mkey [24]

Answer:

pH of buffer =4.75

Explanation:

The pH of buffer solution is calculated using Henderson Hassalbalch's equation:

pH=pKa+log[\frac{[salt]}{[acid]}

Given:

pKa = 3.75

concentration of acid = concentration of formic acid = 1 M

concentration of salt =  concentration of sodium formate = 10 M

pH=3.75+log[\frac{10}{1}]=3.75+1=4.75

pH of buffer =4.75

7 0
3 years ago
Which of these figures probably shows a sugar solution containing a small amount of sugar dissolved in water
Vesnalui [34]

Answer:

The correct answer is Sugar has a greater solubility than sand.

Sugar will easily dissolve in water because it has a lower density than sand, therefore it has a greater solubility.

8 0
3 years ago
Read 2 more answers
Question 5(Multiple Choice Worth 3 points)
Katarina [22]

Answer:

\sqrt{ | {o2}^{2} | }  \times \frac{?}{?}  \sqrt[?]{?}  \times \frac{?}{?}  \sqrt[ |?| ]{?}  \sqrt{?}  \times  \frac{?}{?}

Explanation:

exactly

4 0
3 years ago
Why are electromagnets used in metal scrap yards
Rudik [331]
Theyre temporary magnets, so they can be turned on and off.
7 0
4 years ago
Read 2 more answers
The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine
xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0
3 years ago
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