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notsponge [240]
3 years ago
11

Methods to determine the specific heat capacity of a substance​

Physics
2 answers:
Gre4nikov [31]3 years ago
5 0

The heat capacity and the specific heat

Advocard [28]3 years ago
5 0

Answer:

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What does it mean when something says Expert Verified?<br><br> I am Marking brainliest!
alisha [4.7K]

Answer:

it means an expert verified the answer so its nearly always true

Explanation:

8 0
2 years ago
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A particular car can go from rest to 90 km/h in 10 s. What is its acceleration? (Report your answer in km/h*s)
Romashka-Z-Leto [24]

Answer: 9 km/h

Explanation:i’m pretty sure

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3 years ago
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Water that flows from behind a large dam can cause machines to produce electricity. What change takes place?
lyudmila [28]
The mechanical energy in the falling water is used to spin the generator, and gets transformed into electrical energy.  That's the first choice on the list.
8 0
3 years ago
A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0∘ below the positive x axis. A second vector, B⃗, has a magn
jolli1 [7]

The magnitude of the vector C is 96.32m

<h3>How to solve for the magnitude of vector c</h3>

Ax = AcosθA

= 40 cOS 20

= 37.59

Ay = AsinθA

-40sin20

= -13.68

Bx = B cos θ B

= 75Cos50

= 48.21

By = BsinθB

= 75sin50

= 57.45

Cx = AX + Bx

= 37.59 + 48.21

= 85.8

Cy = Ay + By

= -13.65 + 57.45

= 43.77

The magnitude is solved by

|c| = \sqrt{Cx^{2}+Cy^{2}  }

= √85.8² + 43.77²

= 96.32m

The magnitude of the vector c is 96.32m

Read more on the magnitude of a vector here:

brainly.com/question/3184914

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6 0
1 year ago
In an electric shaver, the blade moves back and forth over a distance of 2.0 mm in simple harmonic motion, with frequency 124 Hz
bagirrra123 [75]

Answer:

(a) A = 1 mm

(b) V_{max}=0.77872 m/s

(c) a_{max}=606.4 m/s^{2}/tex]Explanation:Distance moved back and forth = 2 mm Frequency, f = 124 HzSo, amplitude is the half of the distance traveled back and forth. (a) So, amplitude, A = 1 mm(b) Angular frequency, ω = 2 π f = 2 x 3.14 x 124 = 778.72 rad/s The formula for the maximum speed is given by [tex]V_{max}=\omega \times A

V_{max}=778.72 \times 0.001

V_{max}=0.77872 m/s

(c) The formula for the maximum acceleration is given by

a_{max}=\omega ^{2}A

a_{max}=778.72 ^{2}\times 0.001

[tex]a_{max}=606.4 m/s^{2}/tex]

8 0
3 years ago
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