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3 years ago

5

Which organism has a central brain A.sponge B. hydra C. flatworm D. fish

2 answers:

Scilla [17]3 years ago

8 0

D. Fish
The brain is part of an organism's central nervous system. Simpler organisms such as sponges, hydrae, and flatworms lack the complexity in their central nervous systems to have a brain. A fish, on the other hand, is complex enough to have a central brain.

Elza [17]3 years ago

8 0

Im pretty sure its D. Fish

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Write a scientific report on the clouds seeding using condensation nuclei and showing its relationship to saturated solutions.

Andrej [43]

Answer:

um thats tricky man

Explanation:

i dont even know what nuclei is

6 0

3 years ago

0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati

erastova [34]

Answer:

$[Ag^{+}]=4.2\times 10^{-2}M$

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

$BaCrO_4 (s)\leftrightharpoons Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ba^{2+}][CrO_{4}^{2-}]$

$1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]$

$[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}$

Now,

$Ag_{2}CrO_4(s) \leftrightharpoons 2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]$

$1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})$

$[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}$

$[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M$

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

7 0

3 years ago

H2(g) + Co(g) _CH3OH<br> balance the equation <br>

Tom [10]

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

C: 1a + 0b = 1c

O: 1a + 0b = 1c

H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 1

b = 2

c = 1

4. Substitute Coefficients and Verify Result

CO + 2H2 = CH3OH

L R

C: 1 1 ✔️

O: 1 1 ✔️

H: 4 4 ✔️

8 0

2 years ago

If 0.092J of heat causes a 0.267 degree C temperature change, what mass of water is present?

Thepotemich [5.8K]

Answer:

0.082g

Explanation:

The following data were obtained from the question:

Heat (Q) = 0.092J

Change in temperature (ΔT) = 0.267°C

Specific heat capacity (C) of water = 4.184J/g°C

Mass (M) =..?

Thus, the mass of present can be obtained as follow:

Q = MCΔT

0.092 = M x 4.184 x 0.267

Divide both side by 4.184 x 0.267

M = 0.092 / (4.184 x 0.267)

M = 0.082g

Therefore, mass of water was present is 0.082.

6 0

3 years ago

(2 x 109) x (5 x 105).

Finger [1]

Answer:

114450

Explanation:

2*109 = 218

5*105 = 525

218*525 = 114450

8 0

2 years ago

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