Answer:
a) v2=4147.72 m/s
b) stotal=5.53x10^6 m
Explanation:
a) the length from the center of the earth is equal to:
L1=1x10^6+((6.37/2)x10^6)=4.18x10^6 m
the velocity is 5.14 km/s=5.14x10^3 m/s
the farthest distance is equal to:
L2=2x10^6+((6.37/2)x10^6)=5.18x10^6 m
As the angular momentum is conserved, we have to:
I1=I2
m*L1*v1=m*L2*V2, where m is the mass of satelite
clearing v2:
v2=(L1*V1)/L2=(4.18x10^6*5.14x10^3)/5.18x10^6=4147.72 m/s
b) Using the Newton 3rd law:
vf^2=vi^2+2as
where:
a=g=9.8 m/s^2
vf=0
vi=5.14 km/s
s=?
Clearing s:
s=(vf^2-vi^2)/(2g)=((0-(5.14x10^3)^2)/(2*9.8)=1.35x10^6 m
the total distance is equal to:
stotal=s+L1=1.35x10^6+4.18x10^6=5.53x10^6 m
resultant force = thrust – weight
acceleration = resultant force (newtons, N) divided by mass (kilograms, kg).
Acceleration = resultant force divided by mass
53N/0.56
=94.64 approximately 95
= 95m/s^2
This means that, every second, the speed of the rocket increases by 95m/s2
the S.I unit of Acceleration is meter per second square.
Answer: 78 metres
Explanation:
The average velocity of the bus refers to the rate of change of its distanced travelled in the westward direction per unit time.
Thus, Velocity V = Distance travelled (D)/ time taken (T)
Then, average velocity = 52 metres per hour (mph)
Time taken = 1.5 hour
To get the distance travelled (D), make it the subject formula
D = V x T
D = velocity x time taken
D = 52 mph x 1.5 hour
D = 78 metres
Thus, the bus traveled a distance of 78 metres between the two cities.
