2 years ago

What is the result of 1.58 divided by 3.793 written with the correct number of significant figures?

Physics

1 answer:

NISA [10]2 years ago

8 0

0.41655681518586870551015027682573

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The speed of light in a material is found to be 2.07 x 108 m/s. What is the most likely material from the options below if the s

Paraphin [41]

Answer:

1.3636

Explanation:

Write the expression for the refractive index.

n=c/v

c= speed of light in air

v= speed of light in material

=(3×10^8 m/s)/(2.2×10^8 m/s)

=1.3636

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3 years ago

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As altitude increases in the troposphere and stratosphere, the air temperature does what?

natima [27]

Answer:

Explanation:

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3 years ago

Which of the following statements below is correct?

Mamont248 [21]

C. is correct. when you make a pizza, you see the the meat or pepperoni or cheese heating up and sometimes melted. (thats physical). on the inside the crust in heated and the toppings are cooked (chemical)

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2 years ago

A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5\times 10^{-

joja [24]

Answer:

$5.25\cdot 10^{40} kg m^2/s$

Explanation:

The angular momentum of the pulsar is given by:

$L=m\omega r^2$

where

$m=2.8\cdot 10^{30} kg$ is the mass of the pulsar

$r = 10.0 km = 1\cdot 10^4 m$ is the radius

$\omega$ is the angular speed

Given the period of the pulsar, $T=33.5\cdot 10^{-3} s$ , the angular speed is given by

$\omega=\frac{2\pi}{T}=\frac{2 \pi}{33.5\cdot 10^{-3}s}=187.5 rad/s$

And so, the angular momentum is

$L=m\omega r^2=(2.8\cdot 10^{30}kg)(187.5 rad/s)(1\cdot 10^4 m)^2=5.25\cdot 10^{40} kg m^2/s$

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3 years ago

An ice skater has a moment of inertia of 5.0 kg · m2when her arms are outstretched, and at this time she is spinning at 3.0 rev/

KatRina [158]

Answer:

Explanation:

Given

Initial Moment of Inertia $I_1=5 kg-m^2$

initial Spin $N_1=3 rev/s$

$\omega _1=2\pi N_1=2\pi 3=6\pi rad/s$

Final Moment Moment of Inertia $I_2=2 kg-m^2$

Conserving Angular momentum

$L_1=L_2$

$I_1\omega _1=I_2\omega _2$

$5\times 6\pi=2\times \omega _2$

$\omega _2=15\pi rad/s$

$N_2=\frac{\omega _2}{2\pi }$

$N_2=\frac{15\pi }{2\pi}=7.5 rev/s$

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3 years ago