Answer:
change that a lead is 0.13533
Explanation:
µ = 50000
f(t) = [e^(-t/µ )]/[µ if t ≥ 0
f(t) = 0 if t < 0
τ = 100000
to find out
the chance that a led will last
solution
we know function is f(t) = [e^(-τ/µ)]/[µ]
τ = 100000
so we can say that probability (τ ≥ 100000 ) that is
= 1 - Probability ( τ ≤ 100000 )
that is function of F so
= 1 - f ( 100000 )
that will be
= 1 - ( 1 - [e^(-τ/µ)]/[µ] )
put all value here τ = 100000 and µ = 50000
= 1 - ( 1 - [e^(-100000/50000)] )
= 1 - 1 - [e^(-100000/50000)]
= 0.13533
so that change that a lead is 0.13533
