Answer:
The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit. Kepler's Second Law: the imaginary line joining a planet and the sons sweeps equal areas of space during equal time intervals as the planet orbits.
(Brainliest, please?)
Answer:
Fr = 150 [N]
a = 5 [m/s²]
Explanation:
In order to find the resulting force, we must assume that the thrust force is positive to the right, while the friction force is negative to the left.
![F_{r}=200-50\\F_{r}=150[N]](https://tex.z-dn.net/?f=F_%7Br%7D%3D200-50%5C%5CF_%7Br%7D%3D150%5BN%5D)
Now Newton's Second Law tells us that the sum of the forces or the resulting force is equal to the product of mass by acceleration.
F = m*a
![150 = 30*a\\a=150/30\\a = 5 [m/s^{2} ]](https://tex.z-dn.net/?f=150%20%3D%2030%2Aa%5C%5Ca%3D150%2F30%5C%5Ca%20%3D%205%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
The position of the sun affects the size of a shadow. A person or object blocks more light when the sun is low in the sky. More blocked light makes shadows longer. ... The sky turns dark when your part of Earth spins away from the sun.
Explanation:
Answer:
(a) A = 0.650 m
(b) f = 1.3368 Hz
(c) E = 17.1416 J
(d) K = 11.8835 J
U = 5.2581 J
Explanation:
Given
m = 1.15 kg
x = 0.650 cos (8.40t)
(a) the amplitude,
A = 0.650 m
(b) the frequency,
if we know that
ω = 2πf = 8.40 ⇒ f = 8.40 / (2π)
⇒ f = 1.3368 Hz
(c) the total energy,
we use the formula
E = m*ω²*A² / 2
⇒ E = (1.15)(8.40)²(0.650)² / 2
⇒ E = 17.1416 J
(d) the kinetic energy and potential energy when x = 0.360 m.
We use the formulas
K = (1/2)*m*ω²*(A² - x²) (the kinetic energy)
and
U = (1/2)*m*ω²*x² (the potential energy)
then
K = (1/2)*(1.15)*(8.40)²*((0.650)² - (0.360)²)
⇒ K = 11.8835 J
U = (1/2)*(1.15)*(8.40)²*(0.360)²
⇒ U = 5.2581 J
