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Nadya [2.5K]
4 years ago
5

The forklift exerts a 300.0 N force on the box and moves it 15.0 m into the air. How much work does the forklift do? A. 500 J B.

1.50 * 10^3 J C. 4.50 * 10^3 J D. 0.00 J
Physics
1 answer:
Savatey [412]4 years ago
8 0
Since the equation for Work is as follows....

Work = Force x Displacement

Your equation is...

Work = 300N x 15m

Work = 4,500 Joules 
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Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t
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It’s is D bc it is and idk you should do it
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3 years ago
A spring with spring constant of 34 N/m is stretched 0.12 m from its equilibrium position. How much work must be done to stretch
Nesterboy [21]

Answer:0.253Joules

Explanation:

First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.

F = ke where;

F is the force

k is spring constant = 34N/m

e is the extension = 0.12m

F = 34× 0.12 = 4.08N

To get work done,

Work is said to be done if the force applied to an object cause the body to move a distance from its initial position.

Work done = Force × Distance

Since F = 4.08m, distance = 0.062m

Work done = 4.08 × 0.062

Work done = 0.253Joules

Therefore, work done to stretch the string to an additional 0.062 m distance is 0.253Joules

8 0
4 years ago
A sample of gold has a mass of 30.94 grams and density of 19.32g/cm^3. What volume of space will this sample of gold occupy?
sdas [7]
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3

Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3

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Answer:

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The sinking of cold air creates regions of high pressure and this air travels to lower pressure regions produced by the rising motion of warm air. This process results in air circulation.
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3 years ago
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