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alina1380 [7]
3 years ago
6

Suppose you have 0.100 m3 of co2, at pressure of 2.00 atm, and a temperature of 30.0?c. How many grams of co2 do you have? Expre

ss your answer in grams.
Chemistry
1 answer:
adoni [48]3 years ago
3 0

You would use the ideal gas equation which is Pv=nRt (r=constant=8.314) and (n=moles) and once you’ve found the number of moles you’d do mass= moles* r

P=2 atmospheres (we need this in pascals)

So 2*101325= 202650pa

And we need temperature in kelvin

30+273=303c

Rearrange the ideal gas equation to find moles

n=Pv/nRt

n=202650*0.1/8.314*303

n = 8.044405595

Mass= 8.04*44(molar mass of CO2)

= 352g

If you’re American you would do this differently as I’m a 16 year old at college in the UK

You would keep the atmospheres at 2 but you would change the volume to litres =100L and you would use the atmospheres gas constant= 0.0821

n= 2*100/0.0821*303

n=8.039780836

Mass = 8.04*44

=354g

There is a slight variation in both but that is normal if you’re American use the 2nd answer




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dalvyx [7]

Answer:

C

Explanation:

3 0
3 years ago
If 50% of a radioactive element remains after 4000 years, what is the half-life?
ANTONII [103]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

If 50%, or half, of the element remains after 4000 years, that means the half life must be 4000 years.

Hope this helps!

4 0
3 years ago
In the equation:
Ksenya-84 [330]

Answer:

B) 16 g

Explanation:

  • 2H₂ + O₂ → 2H₂O

First we <u>convert 4 moles of O₂ into moles of H₂</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 4 mol O₂ * \frac{2molH_2}{1molO_2} = 8 mol H₂

Finally we <u>convert 8 moles of H₂ into grams</u>, using <em>its molar mass</em>:

  • 8 mol H₂ * 2 g/mol = 16 g

Thus, the correct answer is option B).

6 0
3 years ago
In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro
Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

Explanation :

Molality : It is defined as the number of moles of solute present in kilograms of solvent.

Formula used :

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}

Solute is, NaBr and solvent is, water.

Given:

Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}

\text{Mass of NaBr}=18.3g

Thus, the mass of sodium bromide added should be, 18.3 grams.

6 0
3 years ago
How many lead atoms are in a cube of lead that has a volume of 2.18 cm3 if the density of lead is 11.3 g/cm3?
Anit [1.1K]
10000000.................
3 0
3 years ago
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