Heat required = Q = 40 kcal
<h3>Further explanation</h3>
Given
mass of 500 g ice
Required
Heat required
Solution
The heat to change the phase can be formulated :
- Q = m.Lf (melting/freezing)
- Q = m.Lv (vaporization/condensation)
Lf=latent heat of fusion
Lv=latent heat of vaporization
Lf for water = 334 kj/kg=6.01 kJ/mol = 80 cal/g
Phase change(ice to water)
Q= 500 g x 80 cal/g
Q = 40 kcal
Answer:
C
Explanation:
Increasing temp causes increased molecule movment in sample 2
Answer:
Hi. Increased evaporation would be the greatest difference.
Explanation:
Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.
Answer:
An atom is a complex arrangement of negatively charged electrons arranged in defined shells about a positively charged nucleus. This nucleus contains most of the atom's mass and is composed of protons and neutrons (except for common hydrogen which has only one proton).
Explanation:
Answer:
1.18 × 10⁷ c
Iron is the anode and zinc is the cathode.
Explanation:
Let's consider the reduction of Zn²⁺.
Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
<em>How many coulombs of charge are needed to produce 61.2 mol of solid zinc?</em>
<em />
We can establish the following relations:
- When 2 moles of electrons circulate, 1 mol of Zn is produced.
- 1 mole of electrons have a charge of 96468 c (Faraday's constant).
Then, for 61.2 mol of Zn:

<em>Identify the anode and cathode when plating an iron nail with zinc.</em>
The anode is where the oxidation takes place and the cathode is where the reduction takes place.
Anode (oxidation): Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻
Cathode (reduction): Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)