Aldehydes and ketones having
α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH).
The initial product formed during this reaction is
β-hydroxy alcohol, which then undergoes dehydration to form
α,β-unsaturated aldehyde or ketone.
In present case, 3,3-dimethyl-2-butanone has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one. The complete reaction product formed is shown below.
Answer:
The answer is C I think..
According to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.
<h3>What is AC?</h3>
It is the flow of electric charges through a conductor is called electric current, if said flow of electric current varies in direction from time to time, we speak of alternating current.
Subatomic particles such as protons and electrons have an electrical charge, a physical property that is manifested by the repulsive and attractive forces that exist between them in AC the electrical charge moves back and forth.
Therefore, we can conclude that according to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.
Learn more about AC here: brainly.com/question/11695848
#SPJ1
Answer:
0.85 Molar Na2O
Explanation:
Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).
(10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.
Molar is a measure of concentration. It is defined as moles/liter. A 1 M solution contains 1 mole of solute per liter of solvent. [200 ml water = 0.2 Liters water.]
In this case, we have 0.161 moles Na2O in 0.200 L of solvent.
(0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O