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victus00 [196]
2 years ago
13

If 33.6 grams of kcl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? 21.2% kc

l 17.5% kcl 14.9% kcl 5.71% kcl
Chemistry
2 answers:
umka21 [38]2 years ago
5 0

Answer:

Concentration in % by mass = 14.9% KCl

Explanation:

<u>Given:</u>

Mass of KCl = 33.6 g

Mass of water = 192 g

<u>To determine:</u>

%w/w of KCl solution

<u>Explanation:</u>

Concentration can be expressed in terms of %w/w which refers to the amount of solute in the total mass of the solution (solute + solvent). This is expressed as:

%w/w = \frac{Mass\ of\ Solute}{Mass\ of \ solute + solvent} *100

For KCl solution

Solute = 33.6 g KCl

Solute + solvent = 33.6 g KCl + 192 g water = 225.6 g

%w/w = \frac{33.6}{33.6+192} *100 = 14.9%

trapecia [35]2 years ago
4 0
Ms ( mass of solute): 33,6g
mss (mass of solution): 33,6+192g = 225,6g
__________________
C = ms/mss × 100%
C = 33.6/225.6 × 100%
C = 14,89% ≈ 14,9%

:•)
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Calcule el volumen de disolución de LiOH a 3.5 M, necesario para neutralizar una disolución de 25 ml de H2SO3 cuya densidad es d
Olin [163]

Respuesta:

0.11 L

Explicación:

Paso 1: Escribir la ecuación balanceada

2 LiOH + H₂SO₃ ⇒ Li₂SO₃ + H₂O

Paso 2: Calcular la masa de solución de H₂SO₃

25 mL de solución de H₂SO₃ tiene una denisdad de 1.03 g/mL.

25 mL × 1.03 g/mL = 28 g

Paso 3: Calcular la masa de H₂SO₃ en 26 g de Solución de H₂SO₃

La riqueza de H₂SO₃ es 60%, es decir, cada 100 g de solución hay 60 g de H₂SO₃.

26 g Sol × 60 g H₂SO₃/100 g Sol = 16 g H₂SO₃

Paso 4: Calcular los moles correspondientes a 16 g de H₂SO₃

La masa molar de H₂SO₃ es 82.07 g/mol.

16 g × 1 mol/82.07 g = 0.19 mol

Paso 5: Calcular los moles de LiOH que reaccionan con 0.19 moles de H₂SO₃

La relación molar de LiOH a H₂SO₃ es 2:1. Los moles de LiOH que reaccionan son 2/1 × 0.19 mol = 0.38 mol.

Paso 6: Calcular el volumen de solución de LiOH

0.38 moles de LiOH están en una solución 3.5 M. El volumen requerido es:

0.38 mol × 1 L/3.5 mol = 0.11 L

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2 years ago
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