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3 years ago

Which of the following is a solution? A. Tomato juice B. Ranch salad dressing C. Brewed coffee D. Muddy water

Chemistry

2 answers:

Firlakuza [10]3 years ago

5 0

I think B.............

Stolb23 [73]3 years ago

3 0

Hey there!

I would go with B. Ranch salad dressing since a solution is a mixture of multiple things.

Hope this helps
Have a great day (:

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when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc

OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =83.6g CO2

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0

3 years ago

MAGNESIUM (Mg) +FLUORINE (F) =

bazaltina [42]

Answer:

MgF2 magnesium fluoride

4 0

3 years ago

What is the molar mass of (NH), CO? 138g 788 968 1448

aleksandr82 [10.1K]

Answer:

The molar mass of $(NH_{4})_{2}CO_{3}$ is 96.8 g/mol

Explanation:

The given molecular formula - $(NH_{4})_{2}CO_{3}$

Individual molar masses of each element in the compound is as follows.

Molar mass of nitrogen - 14.01 g/mol

Molar mass of of hydrogen = 1.008g/mol

Molar mass of carbon = 12.01 g/mol

Molar mass of oxygen =16.00 g/mol

Molar mass of $(NH_{4})_{2}CO_{3}$ is

$2\times[1(14.01)+4(1.008)]+1(12.01)+3(16.00)= 96.8g/mol$

Therefore,The molar mass of $(NH_{4})_{2}CO_{3}$ is 96.8 g/mol

7 0

3 years ago

Consider an ice cube and a hot radiator. Which has the higher thermal energy?

Law Incorporation [45]

The answer to your question is the radiator

8 0

2 years ago

An automobile tire was inflated to a pressure of 24 lb in-2 (1.00 atm = 14.7 lb in-2 ) on a winter’s day when the temperature wa

const2013 [10]

Explanation:

Initial Pressure = 24 lb in-2

Initial Temperature = –5 o C = 268 K (Converting to kelvin temperature)

Final Pressure = ?

Final Temperature = 35 o C = 308 K (Converting to kelvin temperature)

No Change in Volume.

From Gay Lusaac's law; pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.

P1T1 = P2T2

P2 = P1T1 / T2

P2 = 24 * 268 / 308 = 20.88 lb in-2

There would be a drop in pressure as the temperature increases. Appropriate measures should b taken by regularly gauging the pressure of the tire.

6 0

2 years ago