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3 years ago

When a force on an object increases how does the object's acceleration change?

Physics

1 answer:

Sedbober [7]3 years ago

7 0

When force increases, acceleration also increases of the object.....

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nder process costing, costs assigned to goods sold are transferred to the Cost of Goods Sold account from the ________. A perp

Reika [66]

Answer:

Explanation:

Under process costing, costs assigned to goods sold are transferred to the Cost of Goods Sold account from the Finished goods inventory account

The simple reason can be that Earlier than they are transferred to cost of goods sold account and being sold, they are finished goods right before it. So, they are actually transferred from finished goods inventory account only.

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3 years ago

The rotational inertia of a collapsing spinning star changes to 1/5 its initial value. What is the ratio of the new rotational k

Elden [556K]

Answer:

Explanation:

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3 years ago

How much work must be done in the car to slow it from 100km/h to 50km/h

Brilliant_brown [7]

Answer:

$-96.465m$ joule

Explanation:

Let m = mass of the car and v1 = initial velocity and v2 = final velocity

Given.

Initial velocity = 100 km/h

final velocity = 50 km/h

What is work done in the car to slow it from 100km/h to 50km/h?

$v1=100km/h=27.78m/s$

$v2=50km/h=13.89m/s$

The work done in the car to slow it from v1 to v2.

w=Δk

$w=k2-k1$

$w= \frac{1}{2}m(v2)^{2}- \frac{1}{2}m(v1)^{2}$

$w=\frac{1}{2} m(v2-v1)^{2}$

$w=\frac{1}{2}\times m(13.89 -27.78)^{2}$

$w=\frac{1}{2}\times m(-13.89)^{2}$

$w=\frac{1}{2}\times m\times (-192.93)$

$w=-96.465m$ joule.

Therefore, the work done is $-96.465m$ joule

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3 years ago

Bile ______. PLS ANSWER ILL HIVE BRAINLEST ANSWER AND 30 points !!

almond37 [142]

Answer:

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Explanation:

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4 years ago

Read 2 more answers

Amy is in-line skating. Her mass is 50 kg. She is rolling forward (north) on a flat section of road at 10 m/s. The rolling frict

Licemer1 [7]

Answer:

The right solution is "0.50 m/s²". A further explanation is provided below.

Explanation:

The given values are:

Mass,

m = 50 kg

Speed,

v = 10 m/s

Rolling friction acting backward (south),

f = 10 N

Air resistance acting backward (south),

$F_T$ = 15 N

The total force acting will be:

⇒ $F = -f-F$

On substituting the given values, we get

⇒ $=-10-15$

⇒ $=-25 \ N$

Now,

⇒ $a = \frac{F}{m}$

On substituting the given values, we get

⇒ $=\frac{-25}{50}$

⇒ $=-0.50 \ m/s^2$

The horizontal acceleration will be "0.50 m/s²" because the (-)ve sign indicates it in south direction.

4 0

3 years ago