This problems involves the equation, please take a picture.
Either NaI or INa are acceptable formulae for sodium iodide, which is indeed a binary ionic compound. So, the correct answer would be B.
To be able to calculate the number of moles for this problem, for simplicity, we assume that it is an ideal gas. We use the equation PV = nRT. We do as follows:
PV = nRT
n = PV / RT
n = 1(100000) / 0.08206 (27 + 273.15)
n = 4060.04 mol
12.88 x 1000 = 12,880 g
4.77 x 1000 = 4770 cm³
D = mass / volume
D = 12,880 / 4770
D = 2.70 g/cm³
hope this helps!
Answer:
2 K3(PO4) aq + 3NiBr2 aq -------- 6 KBr aq + Ni3(PO4)2 s
Explanation:
