If an object accelerates from rest, with a constant acceleration of 5.4 m/s2, what will its velocity be after 28s?
1 answer:
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Answer:
Part a)
Part b)
Part C)
Part d)
In horizontal direction velocity will remain constant
in vertical direction we have
Explanation:
Part a)
Horizontal speed of the cannon
angle of projection
now we have
horizontal speed =
vertical speed =
now the time taken by it to cover the distance 100 m from the wall
Part b)
Since it hits the ground in the same time
so the height of the castle is given as
Part C)
At highest point of the projection
the vertical component of the velocity will become zero
so we will have
Part d)
In horizontal direction velocity will remain constant
so we have
in vertical direction we have
Part e)
