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Eva8 [605]
3 years ago
11

Help me with this question, please

Physics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

First one is voltage

second is resistance

third is electric current

hope this helped!!

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Monochromatic light of wavelength 720 nm is incident on parallel slits, of width 0.420 mm, separated by 0.560 mm. A diffraction
ki77a [65]

Answer:

1.81×10^-4Io

Explanation:

Check attachment

4 0
4 years ago
I think it is the third one
vekshin1
I’d go with the second one. If the solute is completely dissolved, then it’s unsaturated. If it settles out, it’s saturated. If you heat up a saturated solution and it becomes unsaturated, you have a saturated solution.
3 0
4 years ago
A magnetic field directed along the x-axis changes with time according to B (0.06t2+2.25) T, where t is in seconds. The field is
Gemiola [76]

Answer:

E = 2 \times 10^{-3} V

Explanation:

As we know that rate of change in flux will induce EMF

So here we can

EMF = \frac{d\phi}{dt}

now we have

EMF = \pi r^2\frac{dB}{dt}

now we also know that induced EMF is given by

\int E. dL = \pi r^2\frac{dB}[dt}

E (2\pi r) = \pi r^2\frac{dB}{dt}

E = \frac{r}{2}(\frac{dB}{dt})

now plug in all values in it

E = \frac{0.0133}{2}(0.12 t)

E = 8 \times 10^{-4} (2.50) = 2 \times 10^{-3} V/m

5 0
4 years ago
An green hoop with mass mh = 2.8 kg and radius rh = 0.17 m hangs from a string that goes over a blue solid disk pulley with mass
vladimir2022 [97]
The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N 
the slow masses that must be quicker are the pulley, ring, and the rolling sphere. 
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m 
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m 
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2
6 0
3 years ago
How can I skip class:
Dahasolnce [82]

Answer:

c gl

Explanation:

::::::::::::::::::::::::

3 0
3 years ago
Read 2 more answers
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