<u><em>Answer:</em></u>
2 H₂O ............> 2 H₂ + O₂
<u><em>Explanation:</em></u>
<u>To balance a chemical equation,</u> we need to make sure that the number of moles of each element on the reactants side is equal to the number of moles of that elements on the products side.
<u>For the given equation:</u>
H₂O ............> H₂ + O₂
<u>We need to make sure that:</u>
number of moles of reacting hydrogen = number of moles of produced hydrogen
number of moles of reacting oxygen = number of moles of produced oxygen
<u>1- Let's check the Oxygen:</u>
On the reactant side, we have one mole of oxygen
On the products side, we have two moles of oxygen
To balance this, we can multiply the reactants side by 2.
<u>This will give us:</u>
2 H₂O ............> H₂ + O₂
<u>2- Let's check the Hydrogen:</u>
From part 1, we reached the following equation:
2 H₂O ............> H₂ + O₂
From this equation, we can note that:
On the reactant side, we have 2*2 = 4 moles of hydrogen
On the products side, we have 2 moles of hydrogen
To balance this, we can multiply the hydrogen in the products side by 2
<u>This will give us:</u>
2 H₂O ............> 2 H₂ + O₂
<u>3- Let's check:</u>
The equation we reached in part 2 is:
2 H₂O ............> 2 H₂ + O₂
Checking this equation, we can find that:
We have 2*2 = 4 hydrogen moles on reactants side and 2*2 = 4 hydrogen moles on products side
We have 2 oxygen moles on reactants side and 2 oxygen moles on products side
<u>Therefore,</u>
The equation is balanced
Hope this helps :)
The difference is actually a result of the the depth. Ponds, according to limnology (the study of water bodies) are shallow enough where plants could conceivably grow across the entire surface. ... As a result, there are some very small bodies of water, less than an acre that are deep enough to be called lakes.
Answer:
12.32 L.
Explanation:
The following data were obtained from the question:
Mass of CH4 = 8.80 g
Volume of CH4 =?
Next, we shall determine the number of mole in 8.80 g of CH4. This can be obtained as follow:
Mass of CH4 = 8.80 g
Molar mass of CH4 = 12 + (1×4) = 12 + 4 = 16 g/mol
Mole of CH4 =?
Mole = mass/Molar mass
Mole of CH4 = 8.80 / 16
Mole of CH4 = 0.55 mole.
Finally, we shall determine the volume of the gas at stp as illustrated below:
1 mole of a gas occupies 22.4 L at stp.
Therefore, 0.55 mole of CH4 will occupy = 0.55 × 22.4 = 12.32 L.
Thus, 8.80 g of CH4 occupies 12.32 L at STP.
Answer:
89.6 L.
Explanation:
- For the balanced reaction:
<em>CS₂ + 3O₂ → CO₂ + 2SO₂.</em>
- It is clear that <em>1.0 mole of CS₂</em> with 3.0 moles of O₂ to produce 1.0 mole of CO₂ and <em>2.0 moles of SO₂.</em>
<em></em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CS₂ produces → 2.0 moles of SO₂.
2.0 mole of CS₂ produces → ??? moles of SO₂.
∴ The no. of moles of SO₂ produced = (2.0 mol)(2.0 mol)/(1.0 mol) = 4.0 mol.
- It is known that 1.0 mole of any gas at STP occupies 22.4 L.
<em>∴ 4.0 moles of SO₂ occupy = (4.0)(22.4 L) = 89.6 L.</em>
<em></em>
For the molarity and the percentage of the mass of kcl are mathematically given as
%m/m = 23.1%, molarity = 3.38M
<h3>What is the molarity?</h3>
Generally, the equation for the percentage of the mass of kcl is mathematically given as
(mass of kcl/mass of solution)x 100
therefore
%m/m = (6.31/27.29)x100
%m/m = 23.1%
The molarity
(no of mol/ vol of sol)
molarity = 0.0846mol/0.0250 L
molarity = 3.38M
In conclusion, the molarity is given as
molarity = 3.38M
Read more about Molarity
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