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Charra [1.4K]
3 years ago
13

the individual components of a solution_____.a: can be separated by physical meansb: are chemically combinedc: react to form com

pounds d: require chemical means to be separated
Chemistry
1 answer:
kap26 [50]3 years ago
4 0
I believe the correct response is A. Can be separated by physical means.
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2 years ago
Use the periodic table to choose the element that matches each description.
nika2105 [10]

Using the periodic table to choose the element that matches each description include the following below:

  • Halogen: iodine
  • Group IIA: magnesium
  • Nonreactive: argon
  • Alkali metal: potassium.

<h3>What is a Periodic table?</h3>

This contains elements which are arranged according to the order of their atomic number in a tabular form. There are 18 groups which are the vertical columns present while there are 8 periods which are the horizontal rows present in the periodic table.

Example of an alkali metal is potassium while the non reactive ones include argon, neon etc. Examples of halogens include chlorine, iodine etc. are the ones which have seven electrons in their outer electron shells thereby just requiring one electron to achieve to obtain a stable octet configuration.

These are therefore the elements which match the descriptions provided in this case and is the most appropriate choice.

Read more about Periodic table here brainly.com/question/15987580

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8 0
1 year ago
Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr
Alecsey [184]

Answer:

The wavelength of the emitted photon will be approximately 655 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question, we need to recall Bohr's formula for the energy of each of the orbitals in the hydrogen atom:

E_{n} = -\frac{m_{e}e^{4}}{2(4\pi\epsilon_{0})^2\hbar^{2}}\frac{1}{n^2} = E_{1}\frac{1}{n^{2}}, where:

[tex]m_{e}[tex] = electron mass

e = electron charge

[tex]\epsilon_{0}[tex] = vacuum permittivity

[tex]\hbar[tex] = Planck's constant over 2pi

n = quantum number

[tex]E_{1}[tex] = hydrogen's ground state = -13.6 eV

Therefore, the energy of the emitted photon is given by the difference of the energy in the 3d orbital minus the energy in the 2nd orbital:

[tex]E_{3} - E_{2} = -13.6 eV(\frac{1}{3^{2}} - \frac{1}{2^{2}})=1.89 eV[tex]

Now, knowing the energy of the photon, we can calculate its wavelength using the equation:

[tex]E = \frac{hc}{\lambda}[tex], where:

E = Photon's energy

h = Planck's constant

c = speed of light in vacuum

[tex]\lambda[tex] = wavelength

Solving for [tex]\lambda[tex] and substituting the required values:

[tex]\lambda = \frac{hc}{E} = \frac{1.239 eV\mu m}{1.89 eV}=0.655\mu m = 655 nm[tex], which correspond to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

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3 years ago
What are alternative periodic tables
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Tabulations of chemical elements differing in their organization from the traditional seen periodic system
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Answer:

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