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3 years ago

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the individual components of a solution_____.a: can be separated by physical meansb: are chemically combinedc: react to form com

pounds d: require chemical means to be separated

1 answer:

kap26 [50]3 years ago

4 0

I believe the correct response is A. Can be separated by physical means.

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Wetlands provide habitats for many living things because of their sheltered waters and what other feature?

SIZIF [17.4K]

Answer:

large supply of nutrients.

Explanation:

In a wetland, the soil is covered by water or is almost covered by water. This water may be coming upwards from an underground aquifer. Wetlands are covered by water for most of the year.

They are sheltered waters and do provide habitats for many living things.

Nutrients such as; Carbon sulfur, phosphorus, carbon, and nitrogen are cycled within the soil of wetlands hence wetlands have a large supply of nutrients.

5 0

2 years ago

Iron-60 Express your answer as an isotope.

lys-0071 [83]

Isotopes are variants atoms of the same element, having same number of atomic(proton) number but different number of neutrons and mass number.

Considering iron-60

The atomic number which also equals the number of protons for the element iron as can be seen on the periodic table is 26

The name iron-60 also tells us that this particlar isotope's mass number is 60.
The chemical symbol for Iron is Fe

Now expressing as an isotope iron-60 becomes ⁶⁰₂₆Fe ( very unstable )

Other stable isotopes of Iron include ⁵⁴₂₆Fe , ⁵⁶₂₆Fe, ⁵⁷₂₆Fe and ⁵⁸₂₆Fe

See more here: brainly.com/question/11236150

4 0

3 years ago

Choose the covalent compounds from the following choices Br2 MgS SO2 KF

Novosadov [1.4K]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent Bond

Between 0.4 and 1.7 then it is Polar Covalent Bond

Greater than 1.7 then it is Ionic

For Br₂;

E.N of Bromine = 2.96

E.N of Bromine = 2.96

________

E.N Difference 0.00 (Non Polar Covalent Bond)

For MgS;

E.N of Sulfur = 2.58

E.N of Magnesium = 1.31

________

E.N Difference 1.27 (Ionic Bond)

For SO₂;

E.N of Oxygen = 3.44

E.N of Sulfur = 2.58

________

E.N Difference 0.86 (Polar Covalent Bond)

For KF;

E.N of Fluorine = 3.98

E.N of Potassium = 0.82

________

E.N Difference 3.16 (Ionic Bond)

Result: The Bonds in Br₂ and SO₂ are Covalent in Nature.

3 0

3 years ago

Which of the following possess the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

<u>(a) a solution of pH 3.0</u>

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$11=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-11}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-11}M$

<u>(b) a solution of 0.10 M $NH_3$ </u>

As we know that 1 mole of $NH_3$ is a weak base. So, in a solution it will not dissociates completely.

So, the $OH^-$ concentration will be less than 0.10 M

<u>(c) a solution with a pOH of 12.</u>

We have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-12}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-12}M$

<u>(d) a solution of 0.10 M NaOH</u>

As we know that $NaOH$ is a strong base. So, it dissociates to give $Na^+$ ion and $OH^-$ ion.

So, 0.10 M of $NaOH$ in a solution dissociates to give 0.10 M of $Na^+$ ion and 0.10 M of $OH^-$ ion.

Thus, the $OH^-$ concentration is, 0.10 M

<u>(e) a $1\times 10^{-4}M$ solution of $HNO_2$ </u>

As we know that 1 mole of $HNO_2$ in a solution dissociates to give 1 mole of $H^+$ ion and 1 mole of $NO_2^-$ ion.

So, $1\times 10^{-4}M$ of $HNO_2$ in a solution dissociates to give $1\times 10^{-4}M$ of $H^+$ ion and $1\times 10^{-4}M$ of $NO_2^-$ ion.

The concentration of $H^+$ ion is $1\times 10^{-4}M$

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (1.0\times 10^{-4})$

$pH=4$

Now we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$10=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-10}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-10}M$

From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.

Hence, the correct option is (d)

3 0

3 years ago

The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2

Artyom0805 [142]

Answer:
1.7 * 10^-5

Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles

2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq)
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5

Hope this helps :)

7 0

3 years ago