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Charra [1.4K]
3 years ago
13

the individual components of a solution_____.a: can be separated by physical meansb: are chemically combinedc: react to form com

pounds d: require chemical means to be separated
Chemistry
1 answer:
kap26 [50]3 years ago
4 0
I believe the correct response is A. Can be separated by physical means.
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Do any of u guys know how to do this?
krek1111 [17]
1.)1mps
2)no the slope starts to become steady
3.)there is no motion it stops
6 0
3 years ago
Read 2 more answers
Treatment of 2,4,6-tri-tert-butylphenol with bromine in cold acetic acid gives the compound C18H29BrO in quantitative yield. The
Cloud [144]

Answer:

2,4,6-tri-tert-butylcyclohexa-2,5-dienone

Explanation:

1. Information from the formulas

C₁₈H₃₀O ⟶ C₁₈H₂₉BrO

A Br has replaced an H.

2. Information from the reaction

These look like the conditions for an electrophilic aromatic substitution.

3. Possible mechanism (Fig. 1)

The product must be highly symmetrical, because there are so few NMR signals.

(i) The bromonium ion attacks at the para position, forming a resonance-stabilized carbocation intermediate.

(ii) A bromide ion attacks the H of the hydroxyl group to form 2,4,6-tri-tert-butylcyclohexa-2,5-dienone.

4. Confirmatory evidence (Fig. 2)

(a) Infrared  

1630 cm⁻¹:  C=O stretch

1655 cm⁻¹ : C=C stretch

(b)NMR

1.2 (9h, s):    the 4-tert-butyl group

1.3 (18H, s): the 2- and 6- tert- butyl groups

6.9 (2H, s):    the alkene H atoms

The ratio is 9:18:2.

3 0
3 years ago
HELP PLEASE
WINSTONCH [101]

Answer:

164atm

Explanation:

Given parameters:

Initial pressure  = 150atm

Initial temperature  = 27°C  = 27 + 273 = 300K

New temperature  = 55°C  = 328K

Unknown:

New pressure  = ?

Solution:

At constant volume, the pressure of a given gas varies directly with the absolute temperature.

 Mathematically;

       \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }  

P and T are pressure and temperature values

1 and 2 are the initial and new states

  Insert the parameters and solve;

   \frac{150}{300}   = \frac{P_{2} }{328}  

     300P₂  = 150 x 328

           P₂  = 164atm

4 0
3 years ago
For the following set of pressure/volume data, calculate the new volume of the gas sample after the pressure change is made. Ass
faust18 [17]

Answer:

a. 121 ml, b. 253 ml and c. 2.57 L.

Explanation:

The new volume can be calculated by using the Boyle's law equation:  

P1V1 = P2V2

In the equation, P1 and P2 are the initial and final pressures and V1 and V2 are the initial and final volumes for a real gas at constant temperature.  

a) Based on the given information, P1 = 755 mmHg, V1 = 125 ml, P2 = 780 mm Hg and V2 will be,  

V2 = P1V1/P2

V2 = 755 mmHg × 125 ml/780 mmHg

V2 = 121 ml

b) Based on the given information, P1 = 1.08 atm, V1 = 223 ml, P2 = 0.951 atm and V2 will be,  

V2 = P1V1/P2

V2 = 1.08 atm × 223 ml/0.951 atm

V2 = 253 ml

c) Based on the given information, P1 = 103 kPa, V1 = 3.02 L, P2 = 121 kPa and V2 will be,  

V2 = P1V1/P2

V2 = 103 kPa × 3.02 L/121kPa

V2 = 2.57 L

3 0
4 years ago
At 22 °c an excess amount of a generic metal hydroxide m(oh)2 is mixed with pure water. the resulting equilibrium solution has a
Goshia [24]
The balanced reaction equation:
M(OH)2 ↔ M^2+ + 2(OH)^-

and when the Ksp = [M^2+][OH-]^2
when PH + POH = 14
∴ POH = 14-10.3= 3.7 
and when POH = - ㏒ [OH-]
 3.7 = -㏒[OH-]
∴[OH] = 2x10^-4 
and when [M^2+] = 1/2[OH-]
∴[M^2+] = (2x10^-4) / 2 = 0.0001 M
So, by substitution in Ksp formula:
∴Ksp = (0.0001 * (2x10^-4)^2 = 4x10^-12

5 0
3 years ago
Read 2 more answers
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