Answer:p-hydroxybenzaldehyde is stronger acid to phenol
para-cyanophenol is stronger acid to meta-cyanophenol
o-fluorophenol is stronger acid to p-fluorophenol.
Explanation:
The PKa tool relative to Ph are used to contrast the pairs.
The pKa of phenol is 10. The pKa of p-hydroxybenzaldehyde is 9.24
The pKa for meta-cyanophenol is 8.61 and the pKa for para-cyanophenol is 7.95.
The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature
The pKa is the pH value at which a chemical species will accept or donate a proton. The lower the pKa, the stronger the acid and the greater the ability to donate a proton in aqueous solution.
Chemical reaction: MnSO₄·7H₂O → MnSO₄·H₂O + 6H₂O.
MnSO₄·7H₂O is <span>manganese(II) sulfate heptahydrate.
</span>MnSO₄·H₂O is <span>manganese(II) sulfate monohydrate.
Manganese has oxidation number +2 and sulfate anion has oxidation number -2. For </span><span>crystallization water h</span>epta means seven and mono means one.
a, c, and d are all chemical properties because they give information about how a substance will behave in the given reaction, and can’t be found without the substance undergoing some sort of chemical reaction. b, on the other hand, is a physical property—it can be determined without changing the substance’s chemical composition.
When multiplying numbers, the term with the least significant digits gives how many significant digits will be in the answer. 2.995 has the least with 4 "sig figs", so the answer will have 4 significant digits as well:
2.995/0.16685 = <span>17.9502547198
</span> ↑↑ ↑<span>↑
4 sig figs
So the answer is 17.95.</span>
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