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mart [117]
1 year ago
11

Mercury-197 has a half-life of 3 days. Starting

Chemistry
1 answer:
Ahat [919]1 year ago
4 0

Answer:

2.34 gms left

Explanation:

3 weeks = 21 days   =    7 half lives

300 * (1/2)^7 = 2.34 gms

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If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
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The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

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4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

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3 years ago
How can you distinguish between crystalline allotropic modifications of Sulphur from those of amorphous allotrops?​
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The crystalline allotropes of sulfur are very strong and have a high melting and boiling point while the amorphous allotropes of sulfur are brittle and breaks easily.

<h3>What is a crystalline substance?</h3>

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Also, the crystalline allotropes of sulfur are very strong and have a high melting and boiling point while the amorphous allotropes of sulfur are brittle and breaks easily.

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Hydrochloric acid + aluminum hydroxide ®
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