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3 years ago

True or False: A reference point is stationary

Physics

1 answer:

nataly862011 [7]3 years ago

3 0

Answer:

True

Explanation:

A Reference point is stationary

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What is the unit of pressure? Why is it called a derived unit?<br>Why has SI system

Dovator [93]

Answer:

pascal

Explanation:

its obtained after either division or multiplication

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3 years ago

A cable is 100-m long and has a cross-sectional area of 1.0 mm2. A 1000-N force is applied to stretch the cable. Young's modulus

Blizzard [7]

Answer:

1 m

Explanation:

L = 100 m

A = 1 mm^2 = 1 x 10^-6 m^2

Y = 1 x 10^11 N/m^2

F = 1000 N

Let the cable stretch be ΔL.

By the formula of Young's modulus

$Y=\frac{F\times L}{A\times\Delta L}$

$\Delta L=\frac{F\times L}{A\times\Y}$

$\Delta L=\frac{1000\times 100}{10^{-6}\times10^{11}}$

ΔL = 1 m

Thus, the cable stretches by 1 m.

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2 years ago

Given the 1-m stick shown below, which is held by a thread at its center. Block 1 is 15 N held at the 10 cm mark, while block 2

sattari [20]

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7 0

2 years ago

HELP

Sliva [168]

The stopwatch will be the most useful in determining the kinetic energy of a 50 g battery- powered car traveling a distance of 10 m.

<h3>What is kinetic energy?</h3>

Kinetic energy is the energy of a body possessed due to motion.

This means that for an object to possess kinetic energy, it must be in motion.

The kinetic energy is measured in Joules, which is a product of the mass of the substance and the time taken to travel a distance.

A stopwatch is an instrument used to measure time as one of the components of kinetic energy.

Therefore, the stopwatch will be the most useful in determining the kinetic energy of a 50 g battery- powered car traveling a distance of 10 m.

Learn more about kinetic energy at: brainly.com/question/12669551

8 0

1 year ago

A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces.

Sunny_sXe [5.5K]

Answer: $240\ rad/s^2$

Explanation:

Given

Length of beam $l=2\ m$

mass of beam $m=5\ kg$

Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude

$\tau =F\times l=200\times 2=400\ N.m$

Also, the beam starts rotating about its center

So, the moment of inertia of the beam is

$I=\dfrac{ml^2}{12}=\dfrac{5\times 2^2}{12}\\\\I=\dfrac{5}{3}\ kg.m^2$

Torque is the product of moment of inertia and angular acceleration

$\Rightarrow \tau=I\alpha\\\\\Rightarrow 400=\dfrac{5}{3}\times \alpha\\\\\Rightarrow \alpha =240\ rad/s^2$

7 0

3 years ago