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Aleksandr-060686 [28]
3 years ago
9

Which statement is correct regarding the rate of the reaction below? 3A + B 4X + 2Y The rate of disappearance of B is three time

s greater than that of A. The rate of formation of Y is twice the rate of formation of X. The rate of formation of X is four times the rate of disappearance of B. The rate of disappearance of A is three times the rate of formation of Y.
Chemistry
1 answer:
V125BC [204]3 years ago
7 0
First, let's write the givens in the form of a chemical equation:
3A + B ...................> 4X + 2Y

Now we find that this equation implies the following:
For every 4X and 2Y formation, 3A and 1B must disappear (react).

Comparing this implication to the above choices,  we find that the right answer is: <span>The rate of formation of X is four times the rate of disappearance of B.</span>
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WILL MARK BRAINLIEST FOR THE BEST ANSWER~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
adelina 88 [10]
There are 1,000 milligrams (mg) in one gram:
In 10 grams, there are 10 x 1,000 = 10,000 milligrams. This is a lethal dose of caffeine.

There are 4.05 mg/oz (milligrams/ounce) of caffeine in the soda. 
In a 12 ounce can, there are 4.05 x 12 = 48.6 milligrams.

How many sodas would it take to kill you?
To find this, we divide the lethal dose amount (10,000 mg) by the amount of caffeine per can (48.6 mg).
10,000 ÷ 48.6 = 205.76. 

Since 205 cans is not quite 10,000 mg, technically it would take 206 cans of soda to consume a lethal dose of caffeine. 
7 0
3 years ago
A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to reach the
RSB [31]

Answer:

The concentration of the borax solution is 0.1066 M

Explanation:

Step 1: Dtaa given

Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L

Molarity of H2SO4  = 1.03 M

Volume of the H2SO4 = 2.07 mL = 0.00207 L

Step 2: The balanced equation

Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O

Step 3: Calculate molarity of borax solution

b*Ca*Va = a * Cb*Vb

⇒with B = the coefficient of H2SO4 = 1

⇒with Ca = the concentration of borax = TO BE DETERMINED

⇒with Va = the volume of borax = 0.020 L

⇒with a = the coefficient of borax = 1

⇒with Cb = the concentration of H2SO4 = 1.03 M

⇒with Vb = the volume of H2SO4 = 0.00207 L

Ca*0.020 L = 1.03 M * 0.00207 L

Ca = (1.03 * 0.00207) / 0.020

Ca = 0.1066 M

The concentration of the borax solution is 0.1066 M

6 0
3 years ago
How many moles is in 2.52*10^24 molecules of water?
nataly862011 [7]
Hi friend
--------------
Your answer
-------------------

Water = H2O

Number of molecules in one mole of water = 6.022 × 10²³ [Avogadro's constant]

Given number of molecules = 2.52 × 10²³

So,
------

Number of moles =
\frac{2.52 \times 10 {}^{24} }{6.022 \times 10 {}^{23} }  \\  \\  = 4.184 \: (approximately)

HOPE IT HELPS
3 0
3 years ago
What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E
yulyashka [42]

Answer: K_2SO_3.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = \frac{1.23}{0.63}=2

For S =\frac{0.63}{0.63}=1

For O =\frac{1.89}{0.63}=3

The ratio of K: S:O = 2: 1: 3

Hence the empirical formula is K_2SO_3.

7 0
3 years ago
ANSWER THIS QUICKLY FOR BRAINLIEST!!
kakasveta [241]

Answer:

do good

Explanation:

do good

4 0
3 years ago
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