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Anika [276]
3 years ago
13

In the chemical reaction below, calcium metal and water react to form calcium hydroxide and hydrogen gas. calcium metal + water

→ calcium hydroxide + hydrogen gas Calcium and water are the reactants in this chemical reaction, whereas calcium hydroxide and hydrogen gas are the products that are formed. Once the reaction reaches completion
A.
the products of the reaction will have changed back into the reactants.
B.
the total mass of the products will be less than the original mass of the reactants.
C.
the total mass of the products will be greater than the original mass of the reactants.
D.
the total mass of the products will be equal to the original mass of the reactants.
Chemistry
1 answer:
7nadin3 [17]3 years ago
3 0

D. the total mass of the products will be equal to the original mass of the reactants.

Explanation:

                  Ca + 2H₂O → Ca(OH)₂ + H₂

From this chemical reaction, one can conclude that when the reaction reaches completion, the total mass of the products will be equal to the original mass of the reactants. This is in compliance with the law of conservation of mass.

  • The law of conservation of mass states that matter is the mass of products in a chemical reaction is the same as mass of the reactants.
  • This implies that the mass of the products in a given reaction is the same as that of the reactants.
  • No mass is lost in the process of a chemical change.

Learn more:

law of conservation of mass brainly.com/question/5896850

law of conservation of matter brainly.com/question/2190120

#learnwithBrainly

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1. The reaction below describes cellular respiration. Which compounds are the reactants and which are the
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Answer:

C₆H₁₂O₆ and O₂ are reactant.

CO₂ and H₂O are products.

C₆H₁₂O₆ + 6O₂  →  6CO₂ + 6H₂O + ATP

Explanation:

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1. Aerobic respiration  

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8 0
3 years ago
The following reaction shows sodium carbonate reacting with calcium hydroxide.
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Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

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Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams


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