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3 years ago

I NEED HELP ASAP ILL GIVE 10 POINTS

Chemistry

1 answer:

Naddik [55]3 years ago

3 0

Answer:
That is an illustration of a convergent plate boundary with subduction zone

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There is no overall change in reactants and products whenever a chemical reaction a. goes in just one direction. b. goes in two

rodikova [14]

There is no overall change in reactants and products whenever a chemical reaction reaches equilibrium. It is a fundamental point in a reaction.

<h3>Chemical reactions</h3>

A chemical reaction is a process where one or more reactants interact with an enzyme to generate one or more products.

The equilibrium refers to the state where reactants and products are found in the same concentrations.

During the equilibrium, there is no change in the properties of the reaction and the amounts of substances involved remain the same.

Learn more about chemical reactions:

brainly.com/question/6876669

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2 years ago

Consider the following mechanism for the reaction between nitric oxide and ozone:

swat32

Answer:

A . 2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)

B . Yes

C. O and NO₃

Explanation:

A. The overall reaction is obtained by adding the individual steps in the reaction mechanism where we will get the reactants and product and the intermediates will cancel.

Thus, adding 1+ 2 +3 we get

2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)

B. The reaction intermediates are those that are produced from the initial and/or subsequent steps and are consumed later on in the reaction mechanism, but are neither reactants nor products, they just participate.

From this definition it follows that O(g) and NO₃ are reaction intermediates.

C. O and NO₃

6 0

3 years ago

What type of reaction is this? 2 A1203 (s) + 4 Al(s) + 3 O2 (g)

GaryK [48]

Answer:

Decomposition

Explanation:

7 0

3 years ago

What is the gravitational force between two masses of 1 kg each kept at the distance of 1m?

Eddi Din [679]

Answer:

Explanation:

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3 years ago

A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the

Damm [24]

Answer:

See solution.

Explanation:

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In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

$\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%$