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inysia [295]
2 years ago
8

I NEED HELP ASAP ILL GIVE 10 POINTS​

Chemistry
1 answer:
Naddik [55]2 years ago
3 0
Answer:
That is an illustration of a convergent plate boundary with subduction zone
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What type of reaction is this?<br> 2 A1203 (s) + 4 Al(s) + 3 O2 (g)
GaryK [48]

Answer:

Decomposition

Explanation:

7 0
3 years ago
When an aqueous solution containing hydrochloric acid is just neutralized with an aqueous solution containing sodium hydroxide,
Elza [17]

Answer:

c. salty.

Explanation:

From the question,

The reaction of an acid , i.e hydrochloric acid and a base i.e. , sodium hydroxide takes place , which is a type of neutralization reaction,

Where the acid and a base reacts to give salt along with water .

From the question,

The reaction is as follows -

2 HCl  +  NaOH  →  NaCl  +  H₂O  

Hence, the resulting product is a salt ,

Therefore , the resulting solution would taste like salt.

3 0
3 years ago
I need help fast plzzzzzzzzz
sineoko [7]
What’s the question?
6 0
2 years ago
How is the pH of an acidic substance raised?
BabaBlast [244]

Answer: 4) Concentrate it

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4 0
2 years ago
A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )
Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g)   (1)

The reaction rate of equation (1) is given by:

rate = k*[O_{3}][NO]     (2)

<u>We have:</u>

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s  

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

\frac{\Delta[NO_{2}]}{\Delta t} = rate

\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!                                

5 0
3 years ago
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