Answer:
a) Acceleration of runner is 1.33 m/s²
b) Acceleration of motorcycle is 2.85 m/s²
c) The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity
s = Displacement
a = Acceleration
Equation of motion

Acceleration of runner is 1.33 m/s²

Acceleration of motorcycle is 2.85 m/s²

The runner moves 2.94 m

The motorcycle moves 84.21 m
The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.
Evaporation is more contrasted with the rainfall which is less in the correlation of tropical locale. In tropical locale, protection is very little in light of mists. Alongside temperature, it is the main consideration in adding to changes in the thickness of seawater and consequently sea flow. Saltiness is the way to understanding the worldwide water cycle. 97% of the Earth's free water dwells in the seas. The water cycle is commanded by precipitation and evaporation.
It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s
<u>Explanation:</u>
v = u + at
68.6 ms^-1 = 0 ms^-1 + (9.8 ms^-2 x t)
t = 68.6 ms^-1 / 9.8 ms^-2
t = 7.0s
It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s
Answer:
weigh is 2353.13 N
Explanation:
Given data
density = 7890.00 kg/m3
lighter = 299 N
to find out
the volume of the anchor and weigh in air
solution
from question we can say that
apparent weight = actual weight - buoyant force
we know weight = mg and buoyant force = water density × g
so volume of anchor is = actual weight - apparent weight / buoyant force
volume of anchor is = 299 / 1000 × 9.81
volume of anchor is = 0.0304791 m³
and
weight of anchor is mg
here mass m = density Fe g
density Fe = 7870 from table 14-1
so weight = 7870 × 0.0304791 × 9.81
weigh is 2353.13 N
Answer:
57330.17766 Pa
Explanation:
= Pressure at 4000 m = 61660 Pa
= Density at 4000 m = 0.8194 kg/m³
(Values taken from table of properties of air)
= Velocity of jet = 
= Velocity at max thickness

From Bernoulli's equation

The absolute pressure at this point on the wing is 57330.17766 Pa