The molar mass of calcium carbonate is 100 mg/mmol, so the
number of moles is:
moles CaCO3 = 500 mg / (100 mg/mmol) = 5 mmol
We see that there is 1 mole of Ca per 1 mole of CaCO3,
therefore:
<span>mass Ca = 5 mmol * (40.08 mg/mmol) = 200.22 mg</span>
Answer: 51 grams
Explanation:
Ammonia is a gas with a chemical formula of NH3.
Given that,
Amount of moles of NH3 (n) = ?
Volume of NH3 (v) = 200mL
since the standard unit of volume is liters, convert 200mL to liters
(If 1000mL = 1L
200mL = 200/1000 = 0.2L)
Concentration of NH3 (c) = 1.5M
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
Make n the subject formula
n = c x v
n = 1.50M x 0.2L
n = 3 moles
Now, calculate the mass of ammonia
Amount of moles of NH3 (n) = 3
Mass of NH3 in grams = ?
For molar mass of NH3, use the atomic masses:
N = 14g; H = 1g
NH3 = 14g + (1g x 3)
= 14g + 3g
= 17g/mol
Since, n = mass in grams / molar mass
3 moles = m / 17g/mol
m = 3 moles x 17g/mol
m = 51 grams
Thus, 51 grams of ammonia was dissolved in the solution.
Answer:
A, is a girl balancing on her hands, a red arrow is pointing up and is the same length as an arrow pointing down.
Explanation:
vvEven she was still on her feet the force thats pulling her down is gravity and when you have figure the force that makes it easier so when the 2 arrows are the same size that means the force is balenced
please brailiest please i need one more
Answer:
at the temperature of the experiment is 0.56.
Explanation:
Moles of
= 0.35 mole
Moles of
= 0.40 mole
Volume of solution = 1.00 L
Initial concentration of
=
Initial concentration of
= 
Equilibrium concentration of
=
The given balanced equilibrium reaction is,
Initial conc. 0.35 M 0.40 M 0 M 0M
At eqm. conc. (0.35-x) M (0.40-x) M (x) M (x) M
Given: (0.35-x) = 0.19
x= 0.16 M
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :

Thus
at the temperature of the experiment is 0.56.