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Darina [25.2K]
3 years ago
8

An electron is accelerated through 1.90 103 V from rest and then enters a uniform 1.80-T magnetic field.

Physics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

https://www.slader.com/discussion/question/an-electron-is-accelerated-through-240-times-103-v-from-rest-and-then-enters-a-uniform-170-t-magnetic-field-what-are-a-the-maximum-and-b-the-9e425fbd/

( Here is solution)

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Factor 72x^2 - 8/9<br><br> If you can, please show the steps to solve!
ludmilkaskok [199]
Factor out 8 and then facotr and u get

8/9(9x+1)(9x-1
7 0
3 years ago
A drop of oil of volume 10m it spread out on water to make a circular firm of radius 10m calculate the tickness of the firm
Effectus [21]

Answer:

h = 3.1 cm

Explanation:

Given that,

The volume of a oil drop, V = 10 m

Radius, r = 10 m

We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :

V=\pi r^2 h\\\\h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10}{\pi \times 10^2}\\\\h=0.031\ m\\\\h=3.1\ cm

So, the thickness of the film is equal to 3.1 cm.

8 0
3 years ago
Why does lifting one end of the track lead to constant acceleration?
Rainbow [258]
 <span>We put a motion detector at </span>one end of the track<span> and put a cart on the track. ... Next, we put a motorized fan on the cart and let it push the cart down the track. ... This is what I would expect based on the velocity graph, since </span>acceleration<span> equals the slope of the velocity graph, which remains</span>constant<span> in time.</span>
7 0
3 years ago
Evaluate the gravitational potential energy between two 5.00-kg spherical steel balls separated by a center-tocenter distance of
navik [9.2K]

Answer:

U = 8.30×10-⁹J

Explanation:

m1 = m2 = 5.00kg masses of the spheres

d = 15.0cm = 15×10-²m

r = 5.10cm = 5.10×10-²m

R = d + r = 15×10-² + 5.10×10-²

R = 20.10 ×10-²m = 0.201m

G = 6.67×10-¹¹Nm²/kg²

U = Gm1×m2/R = potential energybetween the spheres

U = 6.67×10-¹¹×5.00×5.00/0.201

U = 8.30×10-⁹J

7 0
3 years ago
The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins
krek1111 [17]

Answer:

Temperature, T = 1542.10 K

Explanation:

It is given that,

The black body radiation emitted from a furnace peaks at a wavelength of, \lambda=1.9\times 10^{-6}\ m

We need to find the temperature inside the furnace. The relationship between the temperature and the wavelength is given by Wein's law i.e.

\lambda\propto \dfrac{1}{T}

or

\lambda=\dfrac{b}{T}

b = Wein's displacement constant

\lambda=\dfrac{2.93\times 10^{-3}}{T}

T=\dfrac{2.93\times 10^{-3}}{\lambda}

T=\dfrac{2.93\times 10^{-3}}{1.9\times 10^{-6}\ m}

T = 1542.10 K

So, the temperature inside the furnace is 1542.10 K. Hence, this is the required solution.

3 0
3 years ago
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