Answer:
.
Explanation:
By Newton's Second Law, the acceleration of an object is proportional to the net force on it. In particular, if the mass of the object is , then
.
Rewrite this equation to obtain:
.
In this case, the assumption is that the force is the only force that is acting on the object. Hence, the net force on the object would also be
Make sure that all values are in their standard units. Forces should be in Newtons (same as , and the acceleration of the object should be in meters-per-second-squared (). Apply the equation to find the mass of the object.
.
Answer:
Explanation:
Check the attachment for the ray diagram
Ray diagrams are important in locating the position of image of an object. It enables us to determine the nature of image formed by an object in from of a mirror or lens.
When drawing ray diagrams to locate the image I of an object O, there are two important steps to follows:
1. Ray emitted from the tip of an object O incidented on the mirror and parallel to the principal axis OP pass towards the focus F of the mirror after reflection.
2. The ray emitting from the tip of the mirror and passing through the centre of curvature of the mirror C undeflected reflects back on the same line of incidence. (Principle of reversibility).
Explanation:
An elastic band is hung on a hook and a mass is hung on the lower end of the band. When the mass is pulled downward and then released, it vibrates vertically. The equation of motion is given by :
Where
s is in centimeters
t is in seconds
Velocity of the particle,
Acceleration of the particle,
Hence, this is the required solution.
Answer:
Explanation:
Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?
from the principle of momentum
In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.
Take note that momentum is the product of mass and velocity
momentum before collision=momentum after collision
mass, m
u=initial velocity of the identical masses
v2=the common velocity after the collision
Note that the collision is inelastic , since they both moved with the same velocity
umcosφ+umcosφ=(m+m)v2cos−θ2
2mucosφ=2mv2cos−θ2
Slow down significantly before the curve in the road