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ddd [48]
3 years ago
15

What is the area of a triangle with a base of 4v^3 and a height of vu^2?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0
Answer:  The area of the triangle is:     " 2v⁴u² square units" ;
                                            or, write as:  " 2v⁴u² units² " .
______________________________________________________
<u>Note</u>:  The formula/equation for the area, "A", of a triangle is:

             A = (1/2) * b * h  ;   or:  A = (b * h) / 2 ; 
______________________________________________________
  in which:   "A" = "area" ; 
                   "b" = "base length" ;
                   "h" = "[perpendicular] height" ; 
______________________________________________________
We are asked to solve for the area, "A" .

We are given:  "b = 4v³ " ;  "h = vu² " ;

So;  to find the area, "A", of the triangle, we plug these given values into the formula; and solve/ simplify:
____________________________________________________
     A = (1/2) * b * h ; 

     A = (1/2) * (4v³) * (vu²) ; 

     A = 2v³ * vu² ;

     A = 2v⁴u²  square units.

Answer:  The area of the triangle is:     " 2v⁴u² square units" ;
                                            or, write as:  " 2v⁴u² units² " .
 ___________________________________________________
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