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Lyrx [107]
3 years ago
13

Where’s the silicone rubber are made ? In a machine, vulcanization… explain please !!!!! I need help

Engineering
1 answer:
Vaselesa [24]3 years ago
4 0

Answer: This is done by heating a large volume of quartz sand to temperatures as high as 1800˚C. The result is pure, isolated silicon, which is allowed to cool and then ground into a fine powder. To make silicone, this fine silicon powder is combined with methyl chloride and heated once again.

Explanation:

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University administrators have developed a Markov model to simulate graduation rates at their school. Students might drop out, r
abruzzese [7]

Solution :

The percentage of the students who have a chance of repeating their current year = 3%

The drop out students for the first year and the sophomores = 6%

Drop out rate of first year and the seniors = 4%

Now for the state space :

S = { first year(1), sophomores(2), juniors(3), seniors(4), graduates(G), Dropouts(D) }

Therefore

the first year students are indicated as '1'

Sophomores are indicated as '2'

Juniors are indicated as '3'

Seniors are indicated as '4

Graduates are indicated as 'G'

Dropouts are indicated as 'D'

The transition diagram is attached below.

The probability of the students who have the chance of repeating their current year = 3/100 = 0.03

Probability of first year dropouts and sophomores = 6/100 = 0.06

Probability of dropout rate of juniors and seniors = 4/100 = 0.04

Therefore, the probability matrix can be made as :

              1        2        3        4       G        D

    \begin{matrix}1\\ 2\\ 3\\ 4\\ G\\ D\end{matrix}      \begin{bmatrix}0.03 & 0.91 & 0 & 0 & 0 & 0.06\\  0& 0.03 & 0.91 & 0 & 0 & 0.06\\  0& 0 & 0.03 & 0.93 & 0 & 0.04\\  0& 0 & 0 & 0.03 & 0.93 & 0.04\\  0& 0 & 0 & 0 & 1 & 0\\  0& 0 & 0 & 0 & 0 & 1\end{bmatrix}  

Here, G represents 'graduates' and D represents 'Dropouts.'

5 0
3 years ago
1. Select the punch that is used to make a mark in metal
s344n2d4d5 [400]

Answer:

pin punch

Explanation:

  1. <em><u>Pin</u></em><em><u> </u></em><em><u>Punch</u></em><em><u> </u></em>
  2. <em><u> </u></em><em><u>pin</u></em><em><u> </u></em><em><u>punch</u></em>
8 0
3 years ago
An alloy fin with a thermal conductivity of 200 W/ሺm ∙ Kሻ has a length of 2.5 cm and a thickness of 3.5 mm. The base of the fin
Svetllana [295]

Answer: heat flux into the fun is 21.714 mW/m^2

Explanation:

Heat flux Q = q/A

q = heat transfer rate W

A = area m^2

q = area * conductivity * temperature gradient

Temperature gradient = difference in temperature of the metal faces divided by the thickness.

Therefore Q = k * ( temp. gradient)

Q = 200 * ((400-20)/3.5*10^-2)

Q = 21714285.71 = 21.714 mW/m^2

Answer 2: convective heat transfer flux between fin and air

is 3800W/m^2

Explanation :

q = hA*(Ts-Ta)

h = convective heat transfer coefficient

Ts = temperature of fin

Ta = temperature of air

Q = q/A

Q = h(Ts-Ta)

Q = 10(400 - 20)

Q = 3800 W/m^2

5 0
4 years ago
The drag coefficient of a car at the design conditions of 1 atm, 25°C, and 90 km/h is to be determined experimentally in a large
SIZIF [17.4K]

Answer: 0.288

Explanation:

Given

Pressure of the car, P = 1 atm

Temperature of the car, T = 25° C

Speed of the car, v = 90 km/h = 90*1000/3600 = 25 m/s

Height of the car, h = 1.25 m

Width of the car, b = 1.65 m

Force acting on the far, F = 220 N

Drag coefficient, C(d) = ?

Using our table A-9, we can trace that the density of air ρ, at the given temperature and pressure of 25 °C and 1 atm, is 1.184 kg/m³

Area = h *b

Area = 1.25 * 1.65

Area = 2.0625 m²

Now we solve for the drag coefficient using the formula

C(d) = F / (1/2 * ρ * A * v²)

C(d) = 220 / (0.5 * 1.184 * 2.0625 * 25²)

C(d) = 220 / (1.221 * 625)

C(d) = 220 / 763.125

C(d) = 0.288

Therefore, the drag coefficient is 0.288

3 0
3 years ago
It was found experimentally that a certain material does not change in volume when subjected to an elastic state of stress. Calc
lora16 [44]
How are you? because i’m great
5 0
3 years ago
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