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3 years ago

Uestion 10

1 answer:

6 0

Tryna boost my score for college stuff could you give me the brainiest and a thanks? Hope you find your answer your looking for!

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I dont undertand this coding problem (Java):

chubhunter [2.5K]

Check The Attachment.

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6 0

4 years ago

For a fluid with a Prandtl Number of 1000.0, the hydrodynamic layer is thinner than the thermal boundary layers. a) True b) Fals

kvv77 [185]

Answer:

(b)False

Explanation:

Given:

Prandtl number(Pr) =1000.

We know that $Pr=\dfrac{\nu }{\alpha }$

Where $\nu$ is the molecular diffusivity of momentum

$\alpha$ is the molecular diffusivity of heat.

Prandtl number(Pr) can also be defined as

$Pr=\left (\dfrac{\delta }{\delta _t}\right )^3$

Where $\delta$ is the hydrodynamic boundary layer thickness and $\delta_t$ is the thermal boundary layer thickness.

So if Pr>1 then hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

In given question Pr>1 so hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

So hydrodynamic layer will be thicker than the thermal boundary layer.

8 0

4 years ago

Two very long concentric cylinders of diameters D1 = 0.42 m and D2 = 0.5 m are maintained at uniform temperatures of T1 = 950 K

MrRa [10]

Answer:

Q=33.34 KW/m

Explanation:

Given that

D₁=0.42 m

A₁= π D₁ L

For unit length

A₁= π D₁ = 0.42 π m²

D₂=0.5 m

A₂= 0.5 π m²

ε₁= 1 ,ε₂= 0.55

T₁=950 K ,T₂ = 500 K

$Q=\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{A_1\epsilon _1}+\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+\dfrac{1}{A_1F_{12}}}$

F₁₁+F₁₂= 1

F₁₁= 0

So, F₁₂= 1

$Q=A_1\dfrac{\sigma (T_1^4-T_2^4)}{\dfrac{1-\varepsilon _1}{\epsilon _1}+A_1\dfrac{1-\varepsilon _2}{A_2\epsilon _2}+1}$

$Q=0.42\pi \dfrac{5.67\times 10^{-8}(950^4-500^4)}{\dfrac{1-1}{1}+0.42\pi\times \dfrac{1-0.55}{0.5\pi\times 0.55}+1}$

Q=33.34 KW/m

3 0

4 years ago

Consider a steady isentropic airflow through a convergent channel with an inletto-exit cross section area ratio of 2. If the inl

Nina [5.8K]

Answer:

for m1=0.2

M2=0.4

for m1=2.5

M2=5

1= channel input

2.channel output

Explanation:

Hello!

To solve this problem follow the steps below!

1.As it is an isentropic system, it means that the temperature of the fluid remains constant, so the volumetric flow is the same, remember that this is calculated by calculating the product between the velocity and the area.

V1A1=V2A2

1= channel input

2.channel output

We can divide both sides of the equation by the speed of sound(V)

$\frac{V1}{V}A1= \frac{V2}{V}A2$

2. The mach number is defined as the ratio between the speed of a fluid and the speed of sound,

we rearrange the equation

M1A1=M2A2

$\frac{M1A1}{A2} =M2$

3.Now considering that the channel is convergent and that the ratio between the areas is 2, we have the following equation (A1 / A2 = 2)

M1(2)=M2

4.Finally we solve for the number of mach indicated (0.2 and 2.5)

for m1=0.2

0.2(2)=M2=0.4

for m1=2.5

2.5(2)=M2=5

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3 years ago

A customer asks why rogue has a vc-turbo engine when turbo engines are for sports cars. What are two ways to respond?.

aniked [119]

Best-in-class gas engine 1 and torque 2 fuel economy and All-new engine to be assembled at Nissan's powertrain facility in Decherd, Tenn.

<h3>Rogue</h3>

Nissan has introduced an all-new Rogue for the 2021 model year, delivering high quality and customer satisfaction through its strong combination of design, safety and technology. Now, for 2022, Nissan is making its best-selling model more powerful, more fuel efficient and more fun to drive with a new 1.5-liter Variable Compression (VC) Turbo engine across the Rogue lineup.

With this information, we can conclude that the vc-turbo engine is a great advance for fuel economy.

Learn more about Nissan in brainly.com/question/24814294

7 0

3 years ago