Answer:
the maximum thermal efficiency is 29%
Explanation:
the maximum efficiency for a thermal engine that works between a cold source and a hot source is the one of a Carnot engine. Its efficiency is given by
Maximum efficiency= 1 - T2/T1
where
T2= absolute temperature of the cold sink (environment)= 20°C + 273 = 293
T2= absolute temperature of the hot source (hot water supply) = 140°C + 273 = 413
therefore
Maximum efficiency= 1 - T2/T1 = 1 - 293/413 = 0,29 =29%
Answer:
Explanation:
volume of 20.9 N
= 20.9 / 11.5 m³
= 1.8174 m³
In one hour 1.8174 m³ flows
in one second volume flowing = 1.8174 / 60 x 60
= 5 x 10⁻⁴ m³
Rate of volume flow = 5 x 10⁻⁴ m³ / s .
Answer:
The work furnished by the compressor is 
The minimum work required for the state to change is 
Explanation:
The explanation to these solution is on the first, second , third and fourth uploaded image respectively
Answer:
engine B is more efficient.
Explanation:
We know that Carnot cycle is an ideal cycle for all working heat engine.In Carnot cycle there are four processes in which two are constant temperature processes and others two are isentropic process.
We also kn ow that the efficiency of Carnot cycle given as follows
Here temperature should be in Kelvin.
For engine A
For engine B
So from above we can say that engine B is more efficient.
Based on the percent moisture content of the dried product, the mass of dried casein produced os 852.3 kg.
<h3>What is the mass of casein in wet casein?</h3>
The mass of casein in 1000 Kg of wet casein is 75% 1000 kg = 750 Kg
Mass of water 250 kg
The mass of casein is constant while the moisture content can be changed.
At 12% moisture content;
750 kg = 88%%
100 % = 100 ×750/88 = 852.27 kg
Therefore, the mass of dried casein produced os 852.3 kg.
Learn more about mass at: brainly.com/question/24658038
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