I think it would increase but I may be wrong
Answer:
0.07 M
Explanation:
Given data:
Volume of H₂SO₄ = 35.00 mL (35/1000 = 0.035 L)
Molarity of KOH =0.1222 M
Volume of KOH = 42.22 mL (42.22/1000 = 0.0422 L)
Molarity /concentration of H₂SO₄ = ?
Solution:
Chemical equation:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Number of moles of KOH:
Molarity = number of moles / volume in L
0.1222 M = number of moles / 0.0422 L
0.0422 L×0.1222 M = number of moles
Number of moles = 0.005 mol
Now we will compare the moles of KOH with H₂SO₄ from balance chemical equation.
KOH : H₂SO₄
2 : 1
0.005 : 1/2×0.005 = 0.0025 mol
Concentration of H₂SO₄:
Molarity = number of moles / volume in L
Molarity = 0.0025 mol / 0.035 L
Molarity = 0.07 M
A grey coloured rock with amphibole and intermediate plagioclase like an andesine would classify as an intermediate rock by Bowen's Reaction Series and by the classification of igneous rocks would probably be like a diorite which is intermediate between a gabbro and a granite. A diorite essentially has no quartz but has the silicates amphibole (like hornblende), mica perhaps a little pyroxene and andesine plagioclase.
Answer:
A
Explanation:
Photosynthesis is reverse combustion, thus, water and carbon dioxide should be reactants. Photosynthesis also needs sunlight, so A it is.
Answer:
Explanation:cool thre answer is 009000000000.1 because you have to add them so ye
