Since Fg=(Gm1m2)/r^2, if the masses are halted the gravitational force will be effected as well. In this case, the gravitational force would be lessened as well.
Answer:
U1 = U2 since the temperature inside the balloon does not change
Q1 - W1 = Q2 - W2
Work done by the balloon = W2 - W1 (on the environment)
W2 - W1 = Q2 - Q1 = 75 J heat put into balloon
So the balloon does 75 J on the environment
Nope Copper is a better conductor
Answer:
V = 0.05 m^3
Explanation:
The weight of the object of mass (m) and volume (V) in water is: 275 N and it is calculated using the buoyancy formula:
275 N = m g - V (dw) g
where (dw) is the density of water (1000 kg/m^3)
The weight of the object in oil is 325 N and it is calculated using the buoyancy formula as:
325 N = m g - V (do) g
where "do" is the density of oil which is: 0.9 x 1000 kg/m^3 = 900 kg/m^3
Therefore, subtracting term by term the two equations:
325 N -275 N = mg - mg - V (do) g + V (dw) g
50 N = V g (dw - do)
50 N = V g (1000 - 900)
50 N = V g (100)
solving for V (which will result in units of m^3):
V = 50 / 981 m^3
V = 0.05 m^3
The distance the bird flies is (17,000 + 600 + 14,400) = 32,000 km.
His average speed is (32,000 km)/(122 days) = 262.3 km/day.
The bird ends up (17,000 - 600 + 14,400) = 30,800 km north
from where he started.
His average velocity is (30,800 km)/(122 days) = 252.5 km/day north .