Question

A charge of 8 nC is placed uniformly on a square sheet of nonconducting material of side 22 cm in the yz plane.(d) What is the magnitude of the electric field to the right (x > 0) of the right face of the slab?

Answer 1

This is a problem dealing with the surface charge density. Based on the given problem above, your charge is 8nc on a square plate of 22 cm x22 cm given that E= (surface charge density)/2ε₀ so answer would be 8nc/22/22/2ε₀. Therefore, the magnitude of the electric field to the right (x>0) of the right face of the slab would be 8nc/22/22/2ε₀.

Answer 2

Answer:

E = 9338.4 N/C

Explanation:

As we know that electric field due to a charged sheet is given by the formula

$E = \frac{\sigma}{2\epsilon_0}$

here we know that

$\sigma$ = charge density

$\sigma = \frac{Q}{A}$

$\sigma = \frac{Q}{L^2}$

$\sigma = \frac{8\times 10^{-9}}{0.22^2}$

$\sigma = 1.65 \times 10^{-7}C/m^2$

now we have

$E = \frac{1.65 \times 10^{-7}}{2(8.85 \times 10^{-12}}$

$E = 9338.4 N/C$