Which can a drop of liquid mercury can be described as?
2 answers:
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Answer:
Time = 6 years
Explanation:
First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:
where,
n = no. of half-life periods = ?
m = initial mass = 86.3 g
m' = remaining mass = 10.8 g
Therefore,
Since the bases are the same. Therefore equating powers:
n = 3
Now we calculate the time:
<u>Time = 6 years</u>
Answer:
67.6m/s
Explanation:
Given parameters:
Initial velocity = 8.2m/s
Acceleration = 9.0m/s²
Time = 6.6s
Unknown:
Final velocity = ?
Solution:
To solve this problem, we use the expression below:
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
9 =
v - 8.2 = 59.4
v = 59.4 + 8.2 = 67.6m/s