A 15.0 kg cart is moving with a velocity of 7.50 m/s down a level hallway. A constant force of 10.0 N acts on the cart, and its velocity become 3.20 m/s. a) What is the change in kinetic energy?
b) How much work was done on the cart?
c) How far did the cart move while the force acted? ...?
1 answer:
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here. Below are the answers: a. <span>DE=421.875-76.8=-345.075 joules (negitive sign means that the energy is transfering out of your system ie slowing down) b. </span><span>work=DE (work done is change in energy)=-345.075 joules c. </span><span>W=f*d </span> <span>d=w/f </span> <span>d=345.075/10 </span> <span>d=34.5075 meters</span>
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