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sp2606 [1]
3 years ago
14

PLEASE HELP I AM ON A TIMED QUIZ

Physics
2 answers:
Leona [35]3 years ago
5 0
The answer is D! Hope this helps , I wish you best of luck on your quiz!
White raven [17]3 years ago
3 0

Answer:

d

Explanation:

I believe its d I thinm

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6. A dumb, bored child wants to see what will happen if they jump off the top of their shed with an umbrella. As you can guess,
ale4655 [162]

Answer:

All i kno is that that kid ain't gonna be ok

Explanation:

if u tell me how to do it ill do it

5 0
3 years ago
Mark all the mesons a) Proton b) Electron c)Anti-top d) Gluon e) Tau Neutrino
Sloan [31]

Answer:

None

Explanation:

Subatomic particles are the particles which are very smaller than the atoms. Elementary particles are the examples of subatomic particles.

Elementary particles are the particles without any sub-structure which means they are not composed of other particles.

The elementary particles are classified into three categories which are discussed below:

(1) Quarks: up, down, top, bottom, strange, and charm.

(2) Leptons: muon, muon neutrino, electrons, electron neutrino,  tau, tau neutrino.

(3) Bosons:  Z bosons, W bosons, Higgs, Gluon, photons.

Mesons are the particles which compose one quark and one anti quarks.

Therefore, in the given list there is no meson.

3 0
3 years ago
Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea
dimaraw [331]

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone =  0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond =  3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

density\density = \dfrac{mass}{volume}

density of stone A

\rho_A = \dfrac{0.52}{0.15}

\rho_A = 3.467\ g/cm^3

density of stone B.

\rho_B = \dfrac{0.42}{0.15}

\rho_B = 2.8\ g/cm^3

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

6 0
3 years ago
A ball is thrown horizontally from the top of a tall cliff. Neglecting air drag, what vertical distance will the ball have falle
adell [148]

The relevant equation to use here is:

y = v0 t + 0.5 g t^2

where y is the vertical distance, v0 is initial velocity = 0, t is time, g = 9.8 m/s^2

 

y = 0 + 0.5 * 9.8 * 3^2

<span>y = 44.1 meters</span>

5 0
3 years ago
Are Constellations based on the magnitude of stars.
Nikolay [14]
Constellations are based off of many Greek and Roman fables. Many of their gods and beliefs are pictured in the stars, which is where we get most of our constellations. Hope this helps!
4 0
3 years ago
Read 2 more answers
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