All categories

3 years ago

What is a factor that affects the outcome of an experiment?

Chemistry

2 answers:

Anni [7]3 years ago

7 0

Answer:

Observation affects the outcome

Y_Kistochka [10]3 years ago

7 0

Answer:

observation, i think

Explanation:

You might be interested in

Stoichmetric calculations must not be based on the limiting reagent true or false

lara31 [8.8K]

Answer:

Ture

Explanation:

Ture

True

5 0

2 years ago

I have an experiment where I put a balloon into an ice bucket and measure its temperature but the lab says

Pavlova-9 [17]

What does the lab say because then i can help :)

7 0

3 years ago

Calculate the rate of dissolution (dM/dt) of relatively hydrophobic drug particles with a surface area of 2.5×103 cm2 and satura

Crank

Answer:

$\large \boxed{\text{1.22 mg/s}}$

Explanation:

We can use the Noyes-Whitney equation to calculate the rate of dissolution.

$\dfrac{\text{d}M}{\text{d}t} = \dfrac{DA(C_{s} - C)}{d}$

Data:

D = 1.75 × 10⁻⁷ cm²s⁻¹

A = 2.5 × 10³ cm²

Cₛ = 0.35 mg/mL

C = 2.1 × 10⁻⁴ mg/mL

d = 1.25 µm

Calculations:

Cₛ - C = (0.35 - 2.1 × 10⁻⁴) mg·cm⁻³ = 0.350 mg·cm⁻³

d = 1.25 µm = 1.25 × 10⁻⁶ m = 1.25 × 10⁻⁴ cm

$\dfrac{\text{d}M}{\text{d}t} = \dfrac{(1.75 \times 10^{-7} \text{cm}^{2}\text{s}^{-1})(2.5 \times 10^{3} \text{ cm}^{2})(0.350\text{ mg$\cdot$cm$^{-3}$})}{1.25 \times 10^{-4} \text{ cm}} = \textbf{1.22 mg/s}\\\\\text{The rate of dissolution is $\large \boxed{\textbf{1.22 mg/s}}$}$

8 0

2 years ago

Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s

True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

CuSO₄: 1 mole
Zn: 1 mole
Cu: 1 mole
ZnSO₄: 1 mole

Being:

Cu: 63.54 g/mole
S: 32 g/mole
O: 16 g/mole
Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
Zn: 65.37 g/mole
Cu: 63.54 g/mole
ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

CuSO₄: 1 moles* 160 g/mole= 160 g
Zn: 1 mole* 65.37 g/mole= 65.37 g
Cu: 1 mole* 63.54 g/mole= 63.54 g
ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g

Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

$mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}$

mass of Zn= 185.49 grams

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

4 0

3 years ago

In principle, the equilibrium in the dehydration of an alcohol could be shifted to the right be removal of water. Why is this ta

Trava [24]

Answer:

See explanation

Explanation:

In this case, we have to remember that if we want to remove water from the reaction vessel we have to heat the vessel. So, we can convert the liquid water into gas water and we can remove it from the vessel. In this case, the products of dehydration for both molecules are (E)-4-methylpent-2-ene and cyclohexene with boiling points of 59.2 ºC and 89 ºC respectively. The boiling point of water is 100 ºC, therefore if we heat the vessel the products and water would leave the system, and the products would be lost.

See figure 1

I hope it helps!

3 0

3 years ago