Answer:
0.010g of C-14 would be later after 50,000 years
Explanation:
The kinetics of radioactive decay follows the equation:
Ln (N / N₀) = -kt
<em>Where N could be taken as mass after time t, </em>
<em>N₀ initial mass = 4.30g;</em>
k is rate constant = ln 2 / t(1/2)
<em>= ln 2 / 5730years = 1.2097x10⁻⁴ years ⁻¹</em>
<em />
Replacing:
Ln (N / 4.30g) = -1.2097x10⁻⁴ years ⁻¹ * 50000 years
N / 4.30 = 2.36x10⁻³
N =
<h3>0.010g of C-14 would be later after 50,000 years</h3>
Answer: Membrane Protiens
Explanation:
In facilitated diffusion, molecules diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers. A concentration gradient exists for these molecules, so they have the potential to diffuse into (or out of) the cell by moving down it.
Answer:
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Answer:
Volumetric flow:
Mixture = 373.55 l/h; Benzene = 310.05 l/h; n-hexane = 63.5 l/h
Mass flow
Mixture = 317.52 kg/h; Benzene = 275.66 kg/h; n-hexane = 41.85 kg/h
Explanation:
First, we can express the mixture mass flow as
The volumetric flow of the mixture is
The mass balance can be written as
And the volumetric flow as
If fluid 2 is n-hexane, we have
The mass flow of n-hexane is 41.85 kg/h.
Its volumetric flow is 63.5 litre/h
The mass flow of benzene can be deducted by difference:
Answer:
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Explanation: just wait