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3 years ago

What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?

1 answer:

8 0

When the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2

2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) * (1L ca(OH)2/0.585 mol Ca(OH)2

= 20.4 L

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10) A student’s calculation w as found to have a 15.6% error, and the actual value w as determined to be 25.7 mL. W hat are the

goblinko [34]

Answer:

The actual value = 25.7 ml

The error = 15.6%

This means that the value of error = 0.156 * 25.7 = 4.0092 ml

Now, the error percentage found means that the student got the value either greater than the actual one with the value of error or less than the actual one with the value of error.

This means that the two possible readings are:

either : 25.7 + 4.0092 = 29.7092 ml

or : 25.7 - 4.0092 = 21.6908 ml

Explanation:

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3 years ago

Pls help it's about density

Vaselesa [24]

1. 100.67
2. 168.55
3. 2.747
So I’m not sure if 2 or 3 are right sorry

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3 years ago

Consider an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen c

blsea [12.9K]

Answer:

(a) The anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Cathodic reaction is: $O_{2} + 2H_{2}O + 4e^{-}$ ⇒ $4OH^{-}$

Anodic reaction is: $Zn$ ⇒ $Zn^{2+} + 2e^{-}$

Explanation:

In the given problem, we have an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen concentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire.

(a) Which electrode will corrode?

The electrode that will corrode is the anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Write half-cell reactions for the anodic reaction and the cathodic reaction.

Cathodic reaction is: $O_{2} + 2H_{2}O + 4e^{-}$ ⇒ $4OH^{-}$

Anodic reaction is: $Zn$ ⇒ $Zn^{2+} + 2e^{-}$

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4 years ago

Why are the temperatures on other objects in the solar system more extreme than the temperatures on the Earth?

musickatia [10]

Hello there!

It is just based on the fact that they are closer or further away from the Sun.

Hope This Helps You!
Good Luck :)

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4 years ago

Explain why the sunlight creates a pattern of decreasing temperature as someone moves from the equator towards areas at higher l

il63 [147K]

The angle of incoming solar radiation influences seasonal temperatures of locations at different latitudes. ... At higher latitudes, the angle of solar radiation is smaller, causing energy to be spread over a larger area of the surface and cooler temperatures.

7 0

3 years ago