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Otrada [13]
3 years ago
11

Julio cubes a number then takes the cube root of the result. He ends up with 20. What number did Julio start with

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Let us say that the number is x.

So the first step that Julio do is to cube the number so that:

x^3

Then the next he did was take cube root of the number, so that:

(x^3)^(1/3)

 

Solving this would result in:

x^(3/3) = x^1 = x

Since he ends up with 20, therefore:

x = 20

 

<span>Julio started and ended with the same number which is 20.</span>

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100 POINTS AND BRAINLY NO LINKS What is the length of the line segment with endpoints (−3, −8) and (10, −8) ?
Anika [276]

Answer:

13 units

given two points: (−3, −8) and (10, −8)

As the y coordinates are same.

use the method:

|x2| + |x1|  where  (x1, y1), (x2, y2)

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Read 2 more answers
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
Please help me!! I'm confused I am not sure what the answer is?
galina1969 [7]

Answer:

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