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Oksanka [162]
3 years ago
13

What is the farthest distance parallaxes can be used to measure star distances from Earth?

Physics
1 answer:
JulsSmile [24]3 years ago
8 0
Using current technology, useful parallax measurements can only be found for stars up to about 340 light years (100 parsecs) away.
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Eli and Andy want to find out which of the two is stronger. Eli pushes a table with a force of 120 newtons while Andy pushes the
Sliva [168]

Answer:

B.  0.50 meters/second^2

Explanation:

Given:

  • mass of table (m) = 10.0 kg
  • Eli's force (F1) = 120 N
  • Andy's force (F2) = -125 N

Arranging Formulas and Substituting Values, Part 1:

  • F = F1 + F2
  • F = 120 + (-125)
  • F = -5 N
  • The -5 means that the table will move along the direction of the force applied by Andy.

Arranging Formulas and Substituting Values, Part 2:

  • m * a = F
  • a = F / M
  • a = -5 / 10.0 kg
  • a = -0.5 m/s^2
3 0
3 years ago
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After the change of state occurs, the temperature _____________.
Artyom0805 [142]
Confused about how much fun you have done to the other day and then I will be sure you guys are gonna right I know you have your own words but you know that I don’t think you know what I mean but you don’t
4 0
4 years ago
Does gravity increase or decrease with greater distance?
PolarNik [594]
Gravitational force decreases with increasing distance. So it decreases!
6 0
3 years ago
A ranger in a national park is driving at 36.2mi / h when a deer jumps into the road 205 ft ahead of the vehicle. After a reac t
Murrr4er [49]

Explanation:

Given that,

Initial speed of a ranger, u = 36.2 mi/h

Distance dove by the ranger, d = 205 ft

Due to the application of brakes, the acceleration reached is 8.83 ft/s².

We need to find the maximum reaction time allowed if she is to avoid hitting the deer.

We know that,

1 mph = 1.46667 ft/s

36.2 mi/h = 53.09 ft/s

Let t is time.

Using second equation of kinematics to find it as follows :

d=ut+\dfrac{1}{2}at^2\\\\ 205=53.09t-\dfrac{1}{2}\times 8.83t^2\\\\4.415t^{2}-53.09t+205=0

The above is a quadratic equation. We need to solve it for t as follows :

t=x=\dfrac{-\left(-53.09\right)-4\left(4.415\right)\left(205\right)}{2\cdot4.415},\dfrac{-\left(-53.09\right)+4\left(4.415\right)\left(205\right)}{2\cdot4.415}\\\\t=-403.98\ s,416.01\ s

Hence, 416.01 seconds is the maximum reaction time allowed if she is to avoid hitting the deer.

8 0
4 years ago
A 605 gram aluminum bar has the following dimensions length 0.75 m, width 0.010 m and height 0.030 m. The bar is clamp at its ce
yarga [219]

Answer:

V= 4999.5 m/s

Explanation:

Given that

mass ,m= 605 gm

Length ,L= 0.75 m

width ,b= 0.01 m

height ,h= 0.03 m

frequency ,f= 3333 Hz

We know that

2 Length = Wavelength

λ= 2 x L

λ = 2 x 0.75 m

λ= 1.5 m

The speed V

V= f x λ

Now by putting the values

V= f x λ

V= 3333 x 1.5 m/s

V= 4999.5 m/s

3 0
3 years ago
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