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3 years ago

When happens when an object becomes positively charged?

2 answers:

6 0

An object becomes positively charged if it loses electrons.
This is because electrons have a negative charge, so the less of them there are in an object, the stronger the positive charge is.

jeyben [28]3 years ago

3 0

Answer:

It loses electrons.

Explanation:

Electrons have a negative charge meaning ,the less electrons there are in an object the stronger the positive charge is.

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You need to produce a set of cylindrical copper wire 3.5 m long that will have a

vazorg [7]

Solution :

We know, resistance is given by :

$R = \dfrac{\rho l}{A}$

$A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2$

Now, we know mass of wire is given by :

$Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram$

Hence, this is the required solution.

8 0

3 years ago

A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides . What is the total surface area of th

Stels [109]

Complete Question

Question 18 (3 points) Solve the problem. (3 points) A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides 2.4m, 2. 3m, 1.5 m. What is the total surface area of the reflector?

A) 33 m2

B) 86 m2

C) 52 m2

D) 34 m2

Answer:

The value is $Area =2.78 \ m^2$

Explanation:

From the question we are told that

The sides are a = 2.4 m

b = 2.3 m

c = 1.5 m

Generally the semi perimeter is mathematically represented as

$s = \frac { a + b + c }{2 }$

=> $s = \frac { 2.4 + 2.3 + 1.5 }{2 }$

=> $s =3.1 \ m$

Generally the using Heron's formula we have that the surface are a is mathematically represented as

$Area = \sqrt{S (S - a) (S - b )(S - c ) }$

=> $Area = \sqrt{3.1 (3.1 - 2.4) (3.1 - 2.3 )(3.1 - 1.5 ) }$

=> $Area =2.78 \ m^2$

6 0

2 years ago

If a weightlifter lifts a 286 kg mass 0.25 meters above his head, how much PEg does the mass have?

vazorg [7]

Answer:

Change in potential energy is 700.7 J.

Explanation:

Given:

Mass of the object is, $m=286$ kg

Height to which the object is raised above his head, $h=0.25$ m

Acceleration due to gravity is, $g=9.8$ m/s²

We know that for a mass $m$ raised to a height $h$ , the change in potential energy is given as:

$\Delta PE=mgh$ , where, $\Delta PE\rightarrow \textrm{Change in Potential Energy}$

Now, plug in the given values and solve.

$\Delta PE=286\times 9.8\times 0.25=700.7\textrm{ J}$

Therefore, the change in the potential energy is 700.7 J.

3 0

3 years ago

Read 2 more answers

Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha

timama [110]

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

$\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}$ .

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

$1 \ kg = 1000 \ g$ ,

Now, we can divide by 1 kg on each side

$\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg}$ ,

$1 = \frac{1000 \ g}{1 \ kg}$ .

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

$mass_{human} = 68 \ kg$

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

$mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}$

$mass_{human} = 68,000 g$

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

$68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal$

So, we would need 10,200 Cal per day.

3 0

2 years ago

She leaves her campsite and runs north for 10 miles turns east and runs 8 miles then turns south and runs 2 miles.whats her dist

Mama L [17]

The distance is 20 miles

Explanation:

Definitions:

Distance is the total length of the path covered by an object during its motion, regardless of the direction of its motion
Displacement is the shortest distance between the initial and final position of the motion, so it also takes into account the direction of motion

In this problem, we want to know the distance covered by the woman. The motion consists of the following parts:

$d_1 = 10 miles$ north