Question

A container with a volume of 3.46 liters contains a gas at a pressure of 1.30 atmospheres and a temperature of 274.27 Kelvins. How many moles of gas are in the container?

Answer 1

PV=nRT, n=(PV)/(RT)
(1.30)(3.46)=(n)(.0821)(274.27)
n=.199755 moles

Answer 2

Answer : The number of moles of gas present in container are, 0.1997 mole

Explanation :

Using ideal gas equation :

$PV=nRT$

where,

n = number of moles of gas  = ?

P = pressure of the gas = 1.30 atm

T = temperature of the gas = 274.27 K

R = gas constant = 0.0821 Latm/moleK

V = volume of gas = 3.46 L

Now put all the given values in the above equation, we get the moles of gas.

$(1.30atm)\times (3.46L)=n\times (0.0821L.atm/mole.K)\times (274.27K)$

$n=0.1997mole$

Therefore, the number of moles of gas present in container are, 0.1997 mole