Final velocity = initial velocity + acceleration * time
v = u + at
v = 3.28 + 2.32 * 2.08
v = 3.28 + 4.83
<u>v = 8.11 m/s</u>
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is 1.10 eV.
What is the maximum kinetic energy Ko of the photoelectrons when light of wavelength 350 nm falls on the same surface?
Use h= 6.63×10-34 J * s for Planck's constant and c= 3.00×10^8 m/s for the speed of light and express your answer in electron volts.
