I think it is a, b, and e. Hope it helps! :)
1.) Two positive charges of 4.3 mC each are separated by 0.25 m.
What is the size and type of force between the two charges? Help
2.) A positive charge of 1.32 x 10-4 C and a negative charge of 9.8 mC
are 0.015 m apart. What is the size and type of force between them? H
3.) Two electrons in an atom are separated by 1.5 x 10-10 m , the typical size
of an atom. What is the size and type of force between them? H
4.) A negative charge of 4.7 mC exerts a repulsive force of 51.0 N on a 2nd charge
0.062 m away. What is the size and polarity (pos or neg) of the 2nd charge? H
5.) A negative charge of 9.3 x 10-5 C exerts an attractive force of 37.4 N when
placed 0.080 m away from a 2nd charge. Find size and polarity of 2nd charge. H
6.) Two positive charges of 3.0 mC exert a repulsive force of 2.0 N on each other.
By what distance are they separated? H
7.) Two charges q1 and q2 are separated by a distance, d and exert a force, F1
on each other. What new force (F2) will exist if:
a) q1 is doubled. H d) d is doubled. H
b) q1 is doubled and q2 is tripled. H e) d is tripled. H
c) q1 is cut in half. H f) q2 is doubled and d is cut in half. H
8.) a) How many electrons are there in 1 C ? H
b) How many excess electrons are on a ball with a charge of -5.26 x 10-17 C ? H
c) How many excess protons are on a ball with a charge of 7.29 x 10-12 C ? H
9.) How many coulombs of negative charge does a 5 gram nickel coin have?
[takes 3 steps; do a) , b) and c) to get answer, don't round off until part c]
a) Find the number of atoms in a nickel.
Its mass is 5 g and nickel has 6.02 x 1023 atoms / 58 g. H
b) Find the number of electrons in the coin. There are 28 electrons / atom. H
c) Find how many coulombs of negative charge in a nickel. 1.6 x 10-19 C / 1 e- H
10.) A lightning bolt transfers 35 C to Earth. How many electrons are transferred? H
Answer:
Explanation:
Velocity at the bottom of height h
= √2gh
deceleration on rough horizontal surface
= μg , μ is coefficient of friction
= .27 x 9.8
= 2.646 m / s²
v² = u² - 2as
0 = 2gh - 2 x 2.646 x 19
h = 2 x 2.646 x 19 / 2 x 9.8
= 5.13 m
from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"
here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?
Answer:
(A) 26 m/s
(B) 32.4 m
(C) v = 15.4 m/s
Explanation:
initial speed (u) = 6.4 m/s
acceleration due to gravity (a) = 9.9 m/s^[2}
time (t) = 2 s
(A) What is its speed after falling for 2.00s?
from the equation of motion v = u + at we can get the speed
v = 6.4 + (9.8 x 2) = 26 m/s
(B) How far does it fall in 2.00s?
from the equation of motion 
we can get the distance covered
s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)
s = 12.8 + 19.6 = 32.4 m
c) What is the magnitude of its velocity after falling 10.0m?
from the equation of motion below we can get the velocity
v = 15.4 m/s
The answer is B because 13 m/s is a greater acceleration than 10 m/s in the same amount of time.
