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Luda [366]
3 years ago
6

Pls help :(( I need help!! Its physics! motion and forces!

Physics
1 answer:
Delvig [45]3 years ago
8 0

Answer: Pedaling your bike : acceleration :: applying the brakes : inertia.

The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.

Edit: I should also add that since you clarified that your unit is motion and forces, Newtons 1st law is the law of inertia. The way to change an objects motion for it to slow down is by applying an additional force. That resistance the bike experiences to slow is the process of inertia. Inertia happens in order to accelerate an object (either by slowing it down, or speeding it up): i.e., the resistance to change.

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Delvig [45]

Answer:

C and D

Explanation:

The guy above me got it wrong

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PAGE NO.: DATE: Why does heat flow from higher temperature to lower temperature body? ​
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The atoms of the system with higher temperature will gain the heat energy and the vibration of these atoms will increase. The atoms or molecules on the system with lower temperature have lower temperature and are not vibrating. ... So, we can say that heat always flows from higher temperature to a lower temperature.

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In a simple 2-bulb series circuit, why does the bulb light when you close the switch?
Nataly [62]

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Because closing the switch completes the circuit.

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A 28 cm hammer is used to pull a nail. If 28.5N of force is
soldi70 [24.7K]

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7.23 Nm

Explanation:

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3 years ago
A 20-kg object is subjected to three forces which produce an acceleration a = -8 m.s^-2 i + 6.0 m.s^-2 j on the object. Two of t
lana66690 [7]

Answer:

F₃ = -151 N i + 96 N j

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

Forces acting on the object

F₁= 3.0 N i + 16.0 N j

F₂ = -12.0 N i+ 8.0 N j

F₃ = F₃x N i +F₃ y N j

x component of the net force on the object

Fx=F₁x+F₂x+F₃ x

Fx = 3.0 N-12.0 N +F₃x

Fx = F₃x - 9 N

y component of the net force on the object

Fy=F₁y+F₂y+F₃ y

Fy =16.0 N+ 8.0 N +F₃y

Fy = F₃y + 24 N

Newton's second law to the object:

a = -8 m/s² i + 6.0 m/s² j

∑Fx = m*ax    m=20 kg , ax = -8 m/s²

F₃x - 9 = 20 *(-8)

F₃x = -160+9

F₃x = -151 N

∑Fy = m*ay    m=20 kg , ay = 6 m/s²

F₃y + 24 =20*( 6 )

F₃y =120 - 24

F₃y = 96 N

F₃ = -151 N i + 96 N j

7 0
3 years ago
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