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Law Incorporation [45]
2 years ago
15

A sheet of aluminum with a rectangular shape is attached to a vertical support by a set of hinges. Assume the sheet is uniform a

nd has height 2.30 m, width 0.895 m, and mass 24.5 kg.
Requried:
a. Determine its moment of inertia (in kg m^2) for rotation on its hinges.
b. Are any pieces of data unnecessary? (Select all that apply.)

1. The height of the sheet is unnecessary.
2. The mass of the sheet is unnecessary.
3. The width of the sheet is unnecessary.
4. No; all of the data are necessary.
Physics
1 answer:
Ivenika [448]2 years ago
6 0
Hey I just got home
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Which is more dense, a pound of rice or a pound of cement?
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I had a question like this one time and the answer is a pound of cement
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3 years ago
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You are standing on a train station platform as a train goes by close to you. As the train approaches, you hear the whistle soun
mojhsa [17]

Answer:

Kindly check explanation

Explanation:

Given the following :

As train approaches ; frequency, f1 = 94Hz

As train recedes; frequency, f2 = 71Hz

Speed of sound in air ; v = 340m/s

A) speed of sound source (speed of train) = vs

From doppler effect :

As the train recedes ;

f2 = fs [v / (v + vs)] - - - - (1)

As train approaches :

f1 = fs [v / (v - vs)] ----- (2)

To find vs equate (1) and (2)

fs [v / (v - vs)] = fs [v / (v + vs)]

f1/f2 = v / (v - vs) ÷ v / (v + vs)

f1 / f2 = v / (v - vs) × (v + vs) / v

f1 / f2 = (v + vs) / (v - vs)

Let f1 / f2 = f

f = (v + vs) / (v - vs)

f (v - vs) = v + vs

fv - fvs = v + vs

fv - v = vs + fvs

v(f - 1) = vs(1 + f)

v(f - 1) / (1 + f) = vs

B)

v(f - 1) / (1 + f) = vs

f = f1 / f2 = 94/71 = 1.32 Hz

340(1.324 - 1) / (1 + 1.324) = vs

vs = 340(0.324) / 2.324

vs = 110.16 / 2.324

vs = 47.40 m/s

C.) To calculate fs, frequency of train, substitute vs into our equation.

f2 = fs [v / (v + vs)]

Following our substitikn we obtain:

fs = (2f / (f + 1))f2

D)

fs = (2f / (f + 1))f2

fs = 2(1.324) / (1.324 +1)) × 71

fs = (2.648 / 2.324) × 71

fs = 1.1394148 × 71

fs = 80.898450

fs = 80.90 Hz

3 0
3 years ago
The reaction of two positively charged objects that are near each other
lilavasa [31]

The objects will repel.

<u>Explanation</u>:

  • Charges are of two types - like and unlike. They are like charges if both are positive or if both are negative. They are unlike charges if one is positive and the other is negative.
  • When two objects of positive charge are near each other, they both have like charges.
  • When two like charges are near each other, they will repel each other.
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5 0
3 years ago
1. (02.02 LC)
Anastaziya [24]
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6 0
3 years ago
A cheerleader lifts his 59.6 kg partner straight up off the ground a distance of 0.749 m before
Airida [17]

m = mass of the partner which the cheerleader lifts = 59.6 kg

h = height to which the partner is lifted by the cheerleader = 0.749 m

g = acceleration due to gravity = 9.8 m/s²

work done by the cheerleader in lifting the partner is same as the potential energy gained by the partner.

W = work done by the cheerleader in lifting the partner

PE = potential energy gained

so  W = PE

potential energy is given as

PE = mgh

hence

W = mgh

inserting the values in the above formula

W = 59.6 x 9.8 x 0.749

W = 437.5 J

this is the work done in lifting the partner once.

the cheerleader does this 30 times , hence the total work done is given as

W' = 30 W

W' = 30 x 437.5

W' = 13125 J


5 0
3 years ago
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