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stiv31 [10]
3 years ago
8

What is the difference between Is it resource that is limited and one that is not limited? Give an example of each

Physics
1 answer:
sveticcg [70]3 years ago
5 0
Limited resources: resources that take a long time to replenish
Example: coal, oil, nuclear gas

Non- limited resource: resources that are constantly being replenished
Example: soil, wind, water

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a kickball is struck with a 15.2 m/s velocity at a 63.0 degree angle. it lands on a rooftop 2.40 s later. how high is the roof?​
Serhud [2]

Refer to the attachment

3 0
2 years ago
Galileo held that measurements of time were _____ and that measurements of distance were ______. absolute; relative
DanielleElmas [232]

Answer:

option A

Explanation:

the correct answer is option A

The given blanks in the question will be filled with Absolute and relative receptively.

time is absolute means the numerical representation of time example 12:00 pm is absolute time.

Measurement of distance is relative. A relative distance is one which is represented with the reference of some other place, it is not an exact value.

6 0
2 years ago
Why would an insurance company want people to avoid risk, like Nick Cannon having to avoid skydiving?
Lina20 [59]
An insurance company wants people to avoid risks because if the person meets with an accsident the expense of the medicines and treatment should be covered by the insurance company.
5 0
2 years ago
Read 2 more answers
What are the relationships of the different types of matter, mass, and the change in the average kinetic energy of particles?
Evgesh-ka [11]

matter = solid, liquid gas.

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6 0
3 years ago
Consider the standing wave pattern below created by a string fixed at both ends. The string is under a tension of 0.98 N and has
Shalnov [3]

Answer:

11.07Hz

Explanation:

Check the attachment for diagram of the standing wave in question.

Formula for calculating the fundamental frequency Fo in strings  is V/2L where;

V is the velocity of the wave in string

L is the length of the string which is expressed as a function of its wavelength.

The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)

Therefore L = 1.5λ

If L = 3.0m

1.5λ = 3.0m

λ = 3/1.5

λ = 2m

Also;

V = √T/m where;

T is the tension = 0.98N

m is the mass per unit length = 2.0g = 0.002kg

V = √0.98/0.002

V = √490

V = 22.14m/s

Fo = V/2L (for string)

Fo = 22.14/2(3)

Fo = 22.14/6

Fo = 3.69Hz

Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo

Frequency of the wave = 3×3.69

Frequency of the wave = 11.07Hz

3 0
3 years ago
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