The answer would be Power
Answer:
statement B is true
Explanation:
since same force is applied by the compressed spring on both masses so their rate of change of momenta must be same and since the lighter block has lesser mass so it must have greater velocity to have an equal change in momentum as of heavier mass.
By relation: 
, 
comparing momenta of above two equations we get
KElighter (2) = KEheavier (4)
KElighter = 2 KEheavier
Answer:
see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas
Explanation:
We will propose this exercise using Archimedes' principle, which establishes that the thrust on a body is equal to the volume of the desalted liquid.
B = ρ g V
The weight of a submerged body is the net force between the weight and the thrust
F_net = W - B
we can write the weight as a function of the density
ρ_body = m / V
m = ρ_body V
W = mg
W = ρ _body g V
we substitute
F_net= ( ρ_body - ρ _fluid) g V
In general this force is directed downwards, we can call this value the apparent weight of the body. This is the weight of the submerged body.
W_aparente = ( ρ_body - ρ _fluid) g V
If some air bubbles formed in this body, the net force of these bubbles is
F_net ’= #_bubbles ( ρ_fluido - ρ_air) g V’
this force is directed upwards
whereby the measured force is
F = W_aparente - F_air
As we can see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas
Answer:
Mass of raft=m1= 1000kg
Mass of paddle=m2=40kg
Speed of paddle=v2=3 m/s
Speed of raft=recoil speed=v1=?
Formula
V1= -(m2/m1)v2= -(40/1000)3= - 0.12m/s
Explanation:
Here the raft has much greater mass as compare the paddle and its velocity will always be negative due to recoil. 1 and 2 with masses and velocities are subscripts.
Grams, Milligram, Microgram.
