When the Sun's energy moves through space, it reaches Earth's atmosphere and finally the surface. This radiant solar energy warms the atmosphere and becomes heat energy. This heat energy is transferred throughout the planet's systems in three ways: by radiation, conduction, and convection.
Let the distance between the towns be d and the speed of the air be s.
distance = speed * time
convert the minutes time into hours.
When flying into the wind, ground speed will be air speed MINUS wind speed, hence the against the wind trip is described by:
d
s−15
=
7
3
return trip is then :
d
s+15
=
7
5
Cross-multiplying both we get the two-variable system:
3d=7∗(s−15)5d=7∗(s+15)
3d=7s−1055d=7s+105
subtract first equation from second equation we get
2d=210d=105km
Substitute the value of d in the above equations for s.
5∗105=7s+1057s=420s=60km/hr
Answer:
Explanation:
Let the potential difference between the plate is V . Then in the first case
Electric field E between plate
E₁ = V / d
where d is separation between plate
When the plate separation becomes d / 2
Electric field E between plate
E₂ = V / d /2
= 2 V / d =2E₁
Or twice the earlier field
Electromagnetic radiation
Answer:
The speed of the soccer ball at height point is less than its initial speed
Explanation:
The initial velocity of the soccer can be written in vector form as
= v cos θ î + v sin θ j
where is initial velocity of the ball
v is the initial speed of the ball
Assume soccer ball is kicked at an angle θ with an horizontal and initial speed vm/s. Its horizontal component will be as,
= v cos θ
= v sin θ
At the maximum height, the vertical component becomes zero. therefore, the velocity of the soccer at the maximum point can be written as,
= v cos θ j
where, is velocity of the soccer ball at maximum height
