If the primary source of atmospheric thermal energy on Earth is energy from the Sun, what conclusion can be made from the diagra
m?
A.
The atmosphere of the Southern Hemisphere is always warmer than that of the Northern Hemisphere.
B.
The atmosphere at the Earth's equator is always warmer than the atmosphere at its poles.
C.
The atmosphere of the Northern Hemisphere is always warmer than that of the Southern Hemisphere.
D.
The atmosphere at the Earth's poles is always warmer than the atmosphere at its equator.
A.
The atmosphere of the Southern Hemisphere is always warmer than that of the Northern Hemisphere.
B.
The atmosphere at the Earth's equator is always warmer than the atmosphere at its poles.
C.
The atmosphere of the Northern Hemisphere is always warmer than that of the Southern Hemisphere.
D.
The atmosphere at the Earth's poles is always warmer than the atmosphere at its equator.
1 answer:
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Answer:
Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:
Now substitute the given values
So
Answer:
A. 3.3 m
Explanation:
Here, we have to use conservation of energy principle.
When the ball is at maximum height, the instantaneous velocity at that point is 0 m/s. So, the kinetic energy of the ball is also 0 at the maximum height. Thus, at maximum height, the energy possessed by the ball is gravitational potential energy only.
Now, when the ball reaches the ground, all the gravitational potential energy changes into kinetic energy because of the conservation of energy.
Therefore, the energy transformation can be given as:
Decrease in potential energy = Increase in Kinetic energy
Decrease in potential energy is given as:
Increase in kinetic energy is given as:
Therefore,
Now, plug in 8 for , 9.8 for
and solve for height
. This gives,
Therefore, the maximum height reached by the ball is 3.3 m.