If the primary source of atmospheric thermal energy on Earth is energy from the Sun, what conclusion can be made from the diagra
m?
A.
The atmosphere of the Southern Hemisphere is always warmer than that of the Northern Hemisphere.
B.
The atmosphere at the Earth's equator is always warmer than the atmosphere at its poles.
C.
The atmosphere of the Northern Hemisphere is always warmer than that of the Southern Hemisphere.
D.
The atmosphere at the Earth's poles is always warmer than the atmosphere at its equator.
A.
The atmosphere of the Southern Hemisphere is always warmer than that of the Northern Hemisphere.
B.
The atmosphere at the Earth's equator is always warmer than the atmosphere at its poles.
C.
The atmosphere of the Northern Hemisphere is always warmer than that of the Southern Hemisphere.
D.
The atmosphere at the Earth's poles is always warmer than the atmosphere at its equator.
1 answer:
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Answer:
The frequency of the photon is .
Explanation:
Given that,
Energy
We need to calculate the energy
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Where, = energy spacing
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Hence, The frequency of the photon is .
Answer:
lower
Explanation:
The lower the value of the coefficient of friction, the lower the resistance to sliding.
The coefficient of friction is the ratio of the frictional force and the normal force pressing two surfaces in contact together.
U =
U is the coefficient of friction
F is the frictional force
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We see that coefficient of friction is directly proportional to frictional force.
Answer:
a)
b)
c)
d) or 18.3 cm
Explanation:
For this case we have the following system with the forces on the figure attached.
We know that the spring compresses a total distance of x=0.10 m
Part a
The gravitational force is defined as mg so on this case the work donde by the gravity is:
Part b
For this case first we can convert the spring constant to N/m like this:
And the work donde by the spring on this case is given by:
Part c
We can assume that the initial velocity for the block is Vi and is at rest from the end of the movement. If we use balance of energy we got:
And if we solve for the initial velocity we got:
Part d
Let d1 represent the new maximum distance, in order to find it we know that :
And replacing we got:
And we can put the terms like this:
If we multiply all the equation by 2 we got:
Now we can replace the values and we got:
And solving the quadratic equation we got that the solution for or 18.3 cm because the negative solution not make sense.
