If the primary source of atmospheric thermal energy on Earth is energy from the Sun, what conclusion can be made from the diagra
m?
A.
The atmosphere of the Southern Hemisphere is always warmer than that of the Northern Hemisphere.
B.
The atmosphere at the Earth's equator is always warmer than the atmosphere at its poles.
C.
The atmosphere of the Northern Hemisphere is always warmer than that of the Southern Hemisphere.
D.
The atmosphere at the Earth's poles is always warmer than the atmosphere at its equator.
A.
The atmosphere of the Southern Hemisphere is always warmer than that of the Northern Hemisphere.
B.
The atmosphere at the Earth's equator is always warmer than the atmosphere at its poles.
C.
The atmosphere of the Northern Hemisphere is always warmer than that of the Southern Hemisphere.
D.
The atmosphere at the Earth's poles is always warmer than the atmosphere at its equator.
1 answer:
You might be interested in
Answer:
37.34372 kg
Explanation:
m = Mass
= Change in temperature
1 denotes water
2 denotes copper
c = Heat capacity
Heat is given by
In this case the heat transfer will be equal
Mass of copper block is 37.34372 kg
1) Distance down the hill: 1752 ft (534 m)
2) Time of flight of the shell: 12.9 s
3) Final speed: 326.8 ft/s (99.6 m/s)
Explanation:
1)
The motion of the shell is a projectile motion, so we can analyze separately its vertical motion and its horizontal motion.
The vertical motion of the shell is a uniformly accelerated motion, so the vertical position is given by the following equation:
(1)
where:
is the initial vertical velocity of the shell, with
and
is the acceleration of gravity
At the same time, the horizontal motion of the shell is a uniform motion, so the horizontal position of the shell at time t is given by the equation
where is the initial horizontal velocity of the shell.
We can re-write this last equation as
(1b)
And substituting into (1),
(2)
where we have choosen the top of the hill (starting position of the shell) as origin (0,0).
We also know that the hill goes down with a slope of from the horizontal, so we can write the position (x,y) of the hill as
(3)
Therefore, the shell hits the slope of the hill when they have same x and y coordinates, so when (2)=(3):
Substituting (1b) into this equation,
Which has 2 solutions:
x = 0 (origin)
and
So, the distance d down the hill at which the shell strikes the hill is
2)
In order to find how long the mortar shell remain in the air, we can use the equation:
where:
x = 1322 ft is the final position of the shell when it strikes the hill
is the initial velocity of the shell
is the angle of projection of the shell
Substituting these values into the equation, we find the time of flight of the shell:
3)
In order to find the final speed of the shell, we have to compute its horizontal and vertical velocity first.
The horizontal component of the velocity is constant and it is
Instead, the vertical component of the velocity is given by
And substituting at t = 12.9 s (time at which the shell strikes the hill),
Therefore, the final speed of the shell is:
Learn more about projectile motion:
#LearnwithBrainly