Answer:
speed when the block had slid 3.40 m is 2.68 m/s
Explanation:
given data
distance = 6.80 m
speed = 3.80 m/s
to find out
speed when the block had slid 3.40 m
solution
we will apply here equation of motion that is
v²-u² = 2×a×s ..............1
here s is distance, a is acceleration and v is speed and u is initial speed that is 0
so put here all value in equation 1 to get a
v²-u² = 2×a×s
3.80²-0 = 2×a×6.80
a = 1.06 m/s²
so
speed when distance 3.40 m
from equation 1 put value
v²-u² = 2×a×s
v²-0 = 2×1.06×3.40
v² = 7.208
v = 2.68
so speed when the block had slid 3.40 m is 2.68 m/s
Answer:
Acceleration is -1.2 m/s² and distance covered is 135 m.
Explanation:
A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking
Given that,
The initial speed of the train, u = 18 m/s
Final speed, v = 0
Time, t = 15 s
We need to find acceleration and distance traveled when braking. Let a is acceleration and distance traveled.
Acceleration,
Using third equation of motion,
Hence, acceleration is -1.2 m/s² and distance covered is 135 m.
Answer:
Explanation:
Power P = .5 mW = .5 x 10⁻³
P = Emax² / 2μo x c , c is velocity of light , μo is permeability of air .
Emax² = P x 2μo x c
= .5 x 10⁻³ x 2 x 4π x 10⁻⁷ x 3 x 10⁸
= 37.68 x 10⁻²
Emax = 6.14 x 10⁻¹
= .614 v/m
b) Bmax = Emax / c
= .614 / 3 x 10⁸
= .2046 x 10⁻⁸ T
= 20.46 x 10⁻¹⁰ T.
Answer
given,
Mass of the solid sphere = 1800 Kg
radius of the sphere,R = 5 m
mass of the small sphere, m = 2.30 Kg
when the Point is outside the sphere the Force between them is equal to
when r>R
When Point is inside the Sphere
when r<R
where r is the distance where the point mass is placed form the center
Now Force calculation
a) r = 5.05 m
[/tex]
F = 1.082 x 10⁻⁸ N
b) r = 2.65 m
Answer:
The universe is the same in every location.
Explanation:
Astronomers are scientist that study the moons, galaxies, stars and planet. When the astronomers say that the universe is homogeneous, they mean that the universe appear the same in every location especially when it is viewed from a distance.
