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Olin [163]
3 years ago
6

Chromosomes move to the middle of the cell during what phase

Chemistry
1 answer:
Alexxandr [17]3 years ago
6 0
The <span>Anaphase stage 

Happy studying!</span>
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How can you tell the mass was conserved in a chemical reaction?
KengaRu [80]

Answer:

\boxed {\boxed {\sf Mass \ of \ products \ = \ mass \ of \ reactants}}

Explanation:

The Law of Conservation of Mass states that mass cannot be created or destroyed.

In a chemical reaction, there are products and reactants. The reactants <em>react</em> and <em>produce</em> the products.

Since mass can't be created or destroyed, the mass of the products must be equal to the mass of the reactants if mass was conserved in a chemical reactions.

6 0
3 years ago
Which statement is not true about the periodic table?
Crazy boy [7]
Answer is A
All elements on the periodic table have a different number of protons that can be represented by its atomic number
4 0
2 years ago
Thermal energy would naturally flow between objects at which temperatures?
marissa [1.9K]

Answer:

i think the answer is letter C. From 35°c to 45°c

Explanation:

sorry if it is wrong

4 0
3 years ago
For each item, choose whether the change is a physical change or chemical change
Aleonysh [2.5K]

Sorry, but where are the ‘items’?

8 0
3 years ago
A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing point depression o
Ludmilka [50]

Answer:

0.297 °C

Step-by-step explanation:

The formula for the <em>freezing point depression </em>ΔT_f is

ΔT_f = iK_f·b

i is the van’t Hoff factor: the number of moles of particles you get from a solute.

For glucose,

       glucose(s) ⟶ glucose(aq)

1 mole glucose ⟶ 1 mol particles     i = 1

Data:

Mass of glucose = 10.20 g

  Mass of water = 355 g

                 ΔT_f = 1.86 °C·kg·mol⁻¹

Calculations:

(a) <em>Moles of glucose </em>

n = 10.20 g × (1 mol/180.16 g)

  = 0.056 62 mol

(b) <em>Kilograms of water </em>

m = 355 g × (1 kg/1000 g)

   = 0.355 kg

(c) <em>Molal concentration </em>

b = moles of solute/kilograms of solvent

  = 0.056 62 mol/0.355 kg

  = 0.1595 mol·kg⁻¹

(d) <em>Freezing point depression </em>

ΔT_f = 1 × 1.86 × 0.1595

        = 0.297 °C

3 0
3 years ago
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